Given the reactions,   X(s)+12O2(g)⟶XO(s)   Δ?=−590.1 kJX(s)+12⁢O2⁡(g)⟶XO(s)   Δ⁢�=−590.1 kJ     XCO3(s)⟶XO(s)+CO2(g)Δ?=+202.7 kJXCO3⁢(s)⟶XO(s)+CO2⁢(g)⁢Δ⁢�=+202.7 kJ   what is Δ?Δ⁢� for this reaction?   X(s)+12O2(g)+CO2(g)⟶XCO3(s)

World of Chemistry, 3rd edition
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Chapter10: Energy
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Given the reactions,

 

X(s)+12O2(g)⟶XO(s)   Δ?=−590.1 kJX(s)+12⁢O2⁡(g)⟶XO(s)   Δ⁢�=−590.1 kJ

 

 

XCO3(s)⟶XO(s)+CO2(g)Δ?=+202.7 kJXCO3⁢(s)⟶XO(s)+CO2⁢(g)⁢Δ⁢�=+202.7 kJ

 

what is Δ?Δ⁢� for this reaction?

 

X(s)+12O2(g)+CO2(g)⟶XCO3(s)

 

Expert Solution
Step 1

Given,

a) X(s) + 12O2(g) ⟶ XO(s)   Δ⁢H = −590.1 kJ
 
b) XCO3(s) ⟶ XO(s) + CO2(g) ΔH = +202.7 kJ
 
What is ∆H for this reaction ?
 
X(s) + 12O2(g) + CO2(g) ⟶ XCO3(s)  ∆H = ?
 
 
 

 

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