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Given: y = x* + 6x + 8 1. Determine the value of h and k by writing the function in the form y = a(x - h)' + k or by applying the formula h= and k= 2. Complete the table of values below. -5 -4 -3 3. Plot the points in the Cartesian Plane and connect them with a smooth curve. 4. Give the following a. vertex: b. x-intercepts: c. y-intercept:, d. axis of symmetry: e. opening of the graph: f. domain: g. range: 5/ 11

Given: y = x* + 6x + 8 1. Determine the value of h and k by writing the function in the form y = a(x - h)' + k or by applying the formula h= and k= 2. Complete the table of values below. -5 -4 -3 3. Plot the points in the Cartesian Plane and connect them with a smooth curve. 4. Give the following a. vertex: b. x-intercepts: c. y-intercept:, d. axis of symmetry: e. opening of the graph: f. domain: g. range: 5/ 11

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 36E
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Domain and Range minium value of y Domain is the set of all real values of x that will give real values for y. The range is the spread of the possible y-values (the minimum y-value to maximum y-value). the cerinu ttend ward the renge erre real rumter then qual -2-) Rarge Veey (0. -3) Seethe p cer gn, then wity to pove infity. Demain R erdse le endip t the from negative domain contain Activity 1: Find Me Out! Given: y = x + 6x + 8 1. Determine the value of h and k by writing the function in the form y = a(x - h) +k or by applying 4ac-b 4 the formula h = and k = 2. Complete the table of values below. -5 -3 -2 -1 y 3. Plot the points in the Cartesian Plane and connect them with a smooth curve. 4. Give the following: a. vertex: b. x-intercepts: с. у-intercept: d. axis of symmetry: e. opening of the graph: f. domain: g. range: 5/ 11 Lesson 2: Characteristics of the Graph of y = afx ± hj2 ± k A. Graphs of ax Considering the graph of y = x and y= -xa whose coordinates of vertex lie at point of origin (0,0). You may notice that the graph of y = x opens upward while y= -x opens downward. Let's formulate the table of values. y-x y x2 -2 -1 1 2 y - -x® 4 1 1 4 y- xa Since the value of a in y = x is positive it yields with an opening of the graph upward while the value of a in y = -x is negative it yields with an -2 -1 1 -4 -1 -1 -4 MATH 9 QUARTER 1 WEEK 8 opening of the graph downward. Hence, the value of a will tell if the graph opens upward and downward Now let us consider the graph of y = x', y = % x and y = 2x.
Transcribed Image Text:Domain and Range minium value of y Domain is the set of all real values of x that will give real values for y. The range is the spread of the possible y-values (the minimum y-value to maximum y-value). the cerinu ttend ward the renge erre real rumter then qual -2-) Rarge Veey (0. -3) Seethe p cer gn, then wity to pove infity. Demain R erdse le endip t the from negative domain contain Activity 1: Find Me Out! Given: y = x + 6x + 8 1. Determine the value of h and k by writing the function in the form y = a(x - h) +k or by applying 4ac-b 4 the formula h = and k = 2. Complete the table of values below. -5 -3 -2 -1 y 3. Plot the points in the Cartesian Plane and connect them with a smooth curve. 4. Give the following: a. vertex: b. x-intercepts: с. у-intercept: d. axis of symmetry: e. opening of the graph: f. domain: g. range: 5/ 11 Lesson 2: Characteristics of the Graph of y = afx ± hj2 ± k A. Graphs of ax Considering the graph of y = x and y= -xa whose coordinates of vertex lie at point of origin (0,0). You may notice that the graph of y = x opens upward while y= -x opens downward. Let's formulate the table of values. y-x y x2 -2 -1 1 2 y - -x® 4 1 1 4 y- xa Since the value of a in y = x is positive it yields with an opening of the graph upward while the value of a in y = -x is negative it yields with an -2 -1 1 -4 -1 -1 -4 MATH 9 QUARTER 1 WEEK 8 opening of the graph downward. Hence, the value of a will tell if the graph opens upward and downward Now let us consider the graph of y = x', y = % x and y = 2x.
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