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- Respiratory Rate Researchers have found that the 95 th percentile the value at which 95% of the data are at or below for respiratory rates in breath per minute during the first 3 years of infancy are given by y=101.82411-0.0125995x+0.00013401x2 for awake infants and y=101.72858-0.0139928x+0.00017646x2 for sleeping infants, where x is the age in months. Source: Pediatrics. a. What is the domain for each function? b. For each respiratory rate, is the rate decreasing or increasing over the first 3 years of life? Hint: Is the graph of the quadratic in the exponent opening upward or downward? Where is the vertex? c. Verify your answer to part b using a graphing calculator. d. For a 1- year-old infant in the 95 th percentile, how much higher is the walking respiratory rate then the sleeping respiratory rate? e. f.The following scatterplot shows the mean annual carbon dioxide (CO,) in parts (CO2) per million (ppm) measured at the top of a mountain and the mean annual air temperature over both land and sea across the globe, in degrees Celsius (C). Complete parts a through h on the right. f) View the accompanying scatterplot of the residuals vs. CO2. Does the scatterplot of the residuals vs. CO, show evidence of the violation of any assumptions behind the regression? 16.800 A. Yes, the outlier condition is violated. 16.725 O B. Yes, the linearity and equal variance assumptions are violated. 16.650 C. Yes, the equal variance assumption is violated. 16.575 O D. No, all assumptioris are okay. 16.500 O E. Yes, all the assumptions are violated. 325.0 337.5 350.0 362.5 CO2 (ppm) OF Yes, the linearity assumption is violated. his vear, What mean temperature doesSuppose you want to estimate the percentage of stat students who passed the departmental final exam. You take a sample 50 stat students and grade their finals first to get an estimate Match the following: all stat students v 50 stat students the percentage of 50 stat students who passed the departmental final exam percentage of all stat students who pased the departmental final exam a stat student v whether or not they passed the final a. individual b. variable C. statistic d. parameter e. population Priv f. sample 21 MacBook Pro esc F1 F2 F3 F4 F5 F6 F7 @ #3 $ 3 4 Q W E R Fab
- 1) What is the line of best fit for this data? a. y =-1.11x+ 11.83; r=-0.9760964904 Average Speed (mi/h) Time (hours) b. y 11.83x- 1. 11; r=0.9527643586 8.5 2.5 c. y= 11.83x –- 1. 11; r=-0.9760964904 7.5 3.75 d. y =-1.11x+ 11.83; r= 0.9527643586. 6.5 4.5 6.0 5.0 5.5 5.5 5.0 6.25 4.0 6.75 3.5 8.75 r notes MacBook Pro * 2$ & 4 5 6 7 8 9. %3D deletc { [ Y ] G H J K L > ? C V N M + || .. .. BSuppose u, and u, are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 9, x = 115.5, s, = 5.04, n = 9, y = 129.9, and s, = 5.37. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) n USE SALT |-19.56 Does the interval suggest that precise information about the value of this difference is available? O Because the interval is so narrow, it appears that precise information is not available. O Because the interval is so wide, it appears that precise information is not available. O Because the interval is so wide, it appears that precise information is available. O Because the interval is so narrow, it appears that precise information is available.6.7 (4) 7 The following three equations were estimated using the 1,534 observations in 401K.RAW: prate = 80.29 + 5.44 mrate + .269 age – .00013 totemp (.045) (.78) (.52) (.00004) R = .100, R² = .098. prate = 97.32 + 5.02 mrate + .314 age – 2.66 log(totemp) (1.95) (0.51) (.044) (.28) R? = .144, R² = .142. prate = 80.62 + 5.34 mrate + .290 age – .00043 totemp (.045) (.78) (.52) (.00009) + .0000000039 totemp? (.0000000010) R? = .108, R² = .106. Which of these three models do you prefer? Why?
- use the previous data its the contueniousation5. Oxygen demand is a term blologists use to describe the axygen needed by fish and other aquatic organisms for survval. The Environmental Protection Agency conducted a study of a wetland area in Marin County, Californla. In this wetland environment, the mean oxygen demand was u=9.9 mg/L, and a= 1.7 mg/L. (Reference: EPA Report 832-R- 93- 005). Let x be a random varlable that represents oxygen demand in this wetland environment. Assume x has a probability distribution that is approximately normal. a. An oxygen demand below 8 mg/L Indicates that some organisms In the wetland environment may be dying. What is the probability that the oxygen demand will fall below 8 mg/L? b. A high oxygen demand can also indicate trouble. An oxygen demand above 12 mg/L may indicate an overabundance of organisms that endanger some types of plant life. What is the probability that the oxygen demand will exceed 12 mg/L?Consider the forecasting model with a simple, linear trend: It = ß1 + Bzt + et Where t is the index for t = 1, 2, ..., T. The OLS estimator of B1, B2 is: E (4t – Ht)(t – t) B2 = Bi = y – Bạf Where "bars" standards for the sample mean e.g. t = E-1 Yt. a Using those formulas, derive the OLS estimator of the regression yt = a1+a2(t – 1) + Et. Compare to Bị and B2. 81 + 82t + ɛt. b Again, using those formulas, derive the OLS estimator of the regression Yt/1000 Compare to B1 and B2.
- Suppose u, and u, are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 5, x = 115.1, s, = 5.05, n = 5, y = 129.2, and s, = 5.36. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) n USE SALT Does the interval suggest that precise information about the value of this difference is available? O Because the interval is so narrow, it appears that precise information is available. o Because the interval is so wide, it appears that precise information is not available. o Because the interval is so narrow, it appears that precise information is not available. Because the interval is so wide, it appears that precise information is available. You may need to use the appropriate table in the Appendix of Tables to answer this question.Suppose 4, and u, are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 7, x = 113.8, s, = 5.09, n = 7, y = 129.5, and s, = 5.38. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) In USE SALT Does the interval suggest that precise information about the value of this difference is available? O Because the interval is so wide, it appears that precise information is not available. Because the interval is so narrow, it appears that precise information is available. O Because the interval is so wide, it appears that precise information is available. Because the interval is so narrow, it appears that precise information is not available.Suppose u, and µ, are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 7, x = 113.3, s, = 5.02, n = 7, y = 129.8, and s, = 5.32. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) n USE SALT |-22.52 |-10.48 Does the interval suggest that precise information about the value of this difference is available? O Because the interval is so wide, it appears that precise information is available. O Because the interval is so narrow, it appears that precise information is not available. O Because the interval is so wide, it appears that precise information is not available. O Because the interval is so narrow, it appears that precise information is available.