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Name: Cystic fibrosis in humans is caused by a recessive allele. A man is kn
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Description: Cystic fibrosis in humans is caused by a recessive allele. A man is known to be a carrier of the cystic fibrosis allele. He marries a phenotypically normal woman. In the general population, the incidence of cystic fibrosis at birth is approximately 1

Science

Biology

Hardy

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter18: Genetics Of Behavior

Section: Chapter Questions

Problem 14QP: A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known...

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Phenylketonuria (PKU) is an inherited disease caused by a recessive allele. Individuals with PKU have two recessive alleles and have very low levels of an enzyme that is needed to properly break down proteins. If a woman and her husband are both carriers and have three children, what is the probability of each of the following? Show your math. (Hint: You can represent your probabilities as fractions or decimals, but probabilities are always between 0 and 1) a. All three children are of normal phenotype. b. One or more of the three children have the disease. c.All three children have the disease.
The allele for albinism is recessive to the allele for normal skin pigmentation. All individuals who are homozygous for this recessive allele (m) are unable to produce the enzyme needed for melanin production and are referred to as albinos. In the following statements, determine the correct genotypes: An albino male (genotype A) whose parents both have normal skin pigmentation (genotype B) marries a woman who does not have albinism (genotype C). This woman’s father is an albino (genotype D). The married couple has three children, two with normal skin pigmentation (genotype E) and one exhibiting albinism (genotype F)
Using the two equations, p + q = 1 and p2 + 2pq + q2 = 1, answer the following question A Hispanic-American couple wants to know their risk for having a child with cystic fibrosis. One parent has no family history of disease, but the other parent has a sibling with cystic fibrosis. Calculate the conditional probability that the couple has a child with cystic fibrosis.
Hemophilia is an X-linked disorder that affects the body’s ability to create blood clots. The allele for normal blood clotting, XH, is dominant over the allele for hemophilia, Xh. An unaffected female that is not a carrier mated with an affected male. Which of the following rows identifies the possible genotypes of the offspring? Select one: a. Female Male XHXH and XHXh XHY and XhY b. Female Male XHXh XHY c. Female Male XHXh XHY and XhY d. Female Male XHXH and XHXh XHY
Sickle cell anemia is a genetically inherited autosomal recessive trait in which results in a condition that there are not enough healthy red blood cells to carry oxygen throughout the body due to the production of red blood cells that are sickle shaped. The frequency of the sickle cell condition is as high as 10% in Central Africa compared to 0.5% in the United States. Calculate the frequency of the normal and carries of the sickle cell condition.
Achondroplasia is a hereditary condition caused by a dominant allele in humans (dominant allele A). This disorder affects bone growth specifically in long bones of the upper and lower limbs by preventing the ossification of bones from cartilage. Determine the genotypes of the parents and offspring for the following family scenarios in a and b below. One parent with the Achondroplasia phenotype and a normal parent have 2 children. Both children have the Achondroplasia phenotype NOTE: You must draw a Punnet square to determine the possible genotypes of te children. When two alternative genotypes are possible for an individual, indicate both.
The following is a summary of the possible sickle-cell genotypes and phenotypes: AA - cojmpletely normal AS - sickle-cell trait (this person has a combination of normal hemoglobin and the abnormal, sickled form of hemoglobin) SS - sickle-cell anemia (all abnormal hemoglobin) If both parents and heterozygous for sickle-cell disease, what are the possible genotypes and phenotypes for their children?
The following is a summary of the possible sickle-cell genotypes and phenotypes: AA - cojmpletely normal AS - sickle-cell trait (this person has a combination of normal hemoglobin and the abnormal, sickled form of hemoglobin) SS - sickle-cell anemia (all abnormal hemoglobin) Make a punnett square for help answering the question: If both parents and heterozygous for sickle-cell disease, what are the possible genotypes and phenotypes for their children?
Classical hemophilia is a sex-linked disease caused by a recessive gene on the X chromosome. (Hemophilia refers to diseases that cause delays in blood clotting.) If a woman who is acarrierof classical hemophilia has children with a normal male, give the ratios of the possible offspring with respect to classical hemophilia. Be sure to state both the genotypes and the phenotypes of each offspring. For genotypes, use X for a normal X chromosome, Xh for an X chromosome with the hemophilia gene, and Y for a normal Y chromosome. For phenotypes, if the offspring is female, be sure to state if homozygous normal, a carrier, or has the disease. If the offspring is a male, be sure to state if normal or has the disease.
Achondroplasia is a hereditary condition caused by a dominant allele in humans (dominant allele A). This disorder affects bone growth specifically in long bones of the upper and lower limbs by preventing the ossification of bones from cartilage. Determine the genotypes of the parents and offspring for the following family scenarios in a and b below. Two parents who have the Achondroplasia phenotype have 4 children where 1 is normal NOTE: You must draw a Punnet square to determine the possible genotypes of te children. When two alternative genotypes are possible for an individual, indicate both.
Below in Figure 1 is a pedigree for a family afflicted by a genetic disorder. In some populations, Cystic fibrosis has an incidence of 1 in 2500 newborns. The carrier frequency calculated from this is 1/25. Analyze the pedigree below assuming the disease is similar to cystic fibrosis in incidence and carrier frequency. However this disease may not have the same type of genetic transmission as cystic fibrosis. Assuming her father is known to NOT be a carrier, calculate the probability that IV1 is a carrier for disease. Use the Χ2 test to determine whether your proposed transmission fits this data.