Hi, in physics I they have The earth's radius is 6.37×106m; it rotates once every 24 hours. I have already found the angular speed ω= 7.3×10−5 rad/s and the point on the equator v= 460 ms. What I'm trying to understand is what is the speed of a point on the earth's surface located at 2/5 of the length of the arc between the equator and the pole, measured from equator? (Hint: what is the radius of the circle in which the point moves?)
Hi, in physics I they have The earth's radius is 6.37×106m; it rotates once every 24 hours. I have already found the angular speed ω= 7.3×10−5 rad/s and the point on the equator v= 460 ms. What I'm trying to understand is what is the speed of a point on the earth's surface located at 2/5 of the length of the arc between the equator and the pole, measured from equator? (Hint: what is the radius of the circle in which the point moves?)
College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter7: Rotational Motion And The Law Of Gravity
Section: Chapter Questions
Problem 2WUE: Math Review (a) Convert 47.0 to radians, using the appropriate conversion ratio. (b) Convert 2.35...
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Hi, in physics I they have The earth's radius is 6.37×106m; it rotates once every 24 hours.
I have already found the angular speed
ω= 7.3×10−5 rad/s and the point on the equator v= 460 ms.
What I'm trying to understand is what is the speed of a point on the earth's surface located at 2/5 of the length of the arc between the equator and the pole, measured from equator? (Hint: what is the radius of the circle in which the point moves?)
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