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- int func(int a, int b) { return (a#include using namespace std; int main() int x=1,y=2; for (int i=0; i<3; i++) e{ x=x*y; 8{ } cout<#include using namespace std; (а) class Fraction{ int x, y; public: Fraction (int a, int b) {x=a; y=b;}; int getx(){return x;} int gety() {return y;} } ; int main() Fraction n(3, 7); ++n; cout << "x/y: " <« n.getx()<< "/" « n.gety()<#include using namespace std; bool isPalindrome(int x) { int n=0,val; val = x; while(x > 0) { n = n * 10 + x % 10; x = x / 10; } } int main() { int n; cin >>n; if(isPalindrome(n)) { cout <#include void main () { int a=5,b=10,c=1; if (a && b>c) { printf("cquestionbank"); } else{ break; } }int x1 = 66; int y1 = 39; int d; _asm { } mov EAX, X1; mov EBX, y1; push EAX; push EBX; pop ECX mov d, ECX; What is d in decimal format?#include<stdio.h> #include<stdarg.h> void fun1(int num, ...); void fun2(int num, ...); int main() { fun1(1, "Apple", "Boys", "Cats", "Dogs"); fun2(2, 12, 13, 14); return 0; } void fun1(int num, ...) { char *str; va_list ptr; va_start(ptr, num); str = va_arg(ptr, char *); printf("%s ", str); } void fun2(int num, ...) { va_list ptr; va_start(ptr, num); num = va_arg(ptr, int); printf("%d", num); }.#include using namespace std; class fraction{ float d,s; public: fraction() { d=0; s=1; fraction(int a, int b) { d=%3; s=b3; } void print() { cout<int sum = 0; for (int i 0; i < 5; i++){ sum += i; } cout << sum;Programming tracing C language Please help it is tracing on c programming kindly input the visual tracing like line where the process start or error Trace the following program: (1) void trace1(int x, int *y){ x = 5; *y =2;printf(“%2d %2d\n”, x, *y);}main( ){int x, y;clrscr( );x = y = 3;trace1(x, &y);printf(“%2d %2d\n”, x, y);getch( );return 0;}JAVA LANGUAGE CODE Postfix Calculator by CodeChum Admin One good implementation of computing infix expressions is to transform them to postfix and then evaluate via the postfix expression. Infix expressions is the common way of writing arithmetic expressions. The binary operator come between them as shown below: 2 * 5 + 9 - 10 / 20 In postfix expressions, the operands come first before the operator: 2 5 * 9 + 10 20 / - A stack can be used to evaluate postfix expressions. The operands are pushed onto the Stack and when an operator is found two operands are popped and the operation is performed and finally the result is pushed back onto the Stack. The final answer will be the lone element of the Stack. Input The first line contains a positive integer n representing the number of postfix expressions. What follows are n postfix expressions themselves. 5 10 20 + 30 15 2 * + 100 20 30 + / 90 20 10 + + 0 / 9 3 - 10 + 2 * Output A single line containing the result of…#include using namespace std; int main() { } int kidsInClass1; int kidsInClass2; int numClasses; double kidsAvgMethodl; double kidsAvgMethod2; kidsInClass1= 3; kidsInClass2 = 2; numClasses = 2; Type the program's output kidsAvgMethodl = static_cast (kidsInClass1 + kidsInClass2) /static_cast (numClasses); kidsAvgMethod2 (kidsInClass1 + kidsInClass2) / numClasses; cout << kidsAvgMethod1 << endl; cout << kidsAvgMethod2 << endl; return 0; =SEE MORE QUESTIONSRecommended textbooks for youEBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENTEBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENT