Tags: C++ array powers of two codechum I need your help! I’m trying to form a spirit bomb and I need all the power I can get! But in order to get power, I need as many powers of 2 as I can get! I can’t seem to tell which of the values are powers of 2 though, but that’s why you’re here! Inputs 1. Size of the integer array 2. Elements of the integer array

Tags: C++ array powers of two codechum I need your help! I’m trying to form a spirit bomb and I need all the power I can get! But in order to get power, I need as many powers of 2 as I can get! I can’t seem to tell which of the values are powers of 2 though, but that’s why you’re here! Inputs 1. Size of the integer array 2. Elements of the integer array

New Perspectives on HTML5, CSS3, and JavaScript

6th Edition

ISBN:9781305503922

Author:Patrick M. Carey

Publisher:Patrick M. Carey

Chapter14: Exploring Object-based Programming: Designing An Online Poker

Section14.1: Visual Overview: Custom Objects, Properties, And Methods

Problem 7QC

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bool add(int anInt)// Pre: contains(anInt) ? size() <= MAX_SIZE : size() < MAX_SIZE// Post: If contains(anInt) returns false, anInt has been// added to the invoking IntSet as a new element and// true is returned, otherwise the invoking IntSet is// unchanged and false is returned.// bool remove(int anInt)// Pre: (none)// Post: If contains(anInt) returns true, anInt has been// removed from the invoking IntSet and true is// returned, otherwise the invoking IntSet is unchanged// and false is returned. bool add(int anInt); bool remove(int anInt); bool IntSet::add(int anInt){ if(used <= data[MAX_SIZE]) // check if the array is not full { return contains(used); //if not full then return to data } return false;} bool IntSet::remove(int anInt){ cout << "remove() is not implemented yet..." << endl; return false; // dummy value returned}
Design and implement a service that simulates PHP loops. Each of the three loop variants should be encapsulated in an object. The service can be controlled via a parameter and execute three different simulations. The result is returned as JSON. The input is an array consisting of the letters $characters = [A-Z]. -The For loop should store all even letters in an array.-The Foreach loop simulation is to create a backward sorted array by For loop, i.e. [Z-A] .-The While loop should write all characters into an array until the desired character is found. Interface:-GET Parameter String: loopType ( possible values: REVERSE, EVEN, UNTIL )-GET parameter String: until (up to which character) Output:JSON Object: {loopName: <string>, result: <array> }
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For this project you will be implementing a new data structure called LinkedGrid. This is a linked type data structure version of a 2D array. The LinkedGrid can support any combination of dimensions (n x n, n x m, or m x n, where n > m) This data structure has a singly linked system which allows you to traverse the grid in multiple directions in addition to allowing you to retrieve specific rows and columns. The following diagram gives a rough visual of this data structure. NOTE: Your LinkedGrid MUST work with any number of nodes, the picture only shows twelve as an idea. You may not hardcode only twelve nodes... There should be no public functions other than the ones given to you You may implement any other private functions you feel are necessary to help you implement the given constructors / public functions Complete ALL methods with "TO DO" in LinkedGrid.java import java.util.ArrayList; public class LinkedGrid<E>{private int numRows;private int numCols; private…
Q1. Implement a SnapshotArray that supports the following interface: SnapshotArray(int length) initializes an array-like data structure with the given length. Initially, each element equals 0. void set(index, val) sets the element at the given index to be equal to val. int snap() takes a snapshot of the array and returns the snap_id: the total number of times we called snap() minus 1. int get(index, snap_id) returns the value at the given index, at the time we took the snapshot with the given snap_id Example 1: Input: ["SnapshotArray","set","snap","set","get"] [[3],[0,5],[],[0,6],[0,0]] Output: [null,null,0,null,5] Explanation: SnapshotArray snapshotArr = new SnapshotArray(3); // set the length to be 3 snapshotArr.set(0,5); // Set array[0] = 5 snapshotArr.snap(); // Take a snapshot, return snap_id = 0 snapshotArr.set(0,6); snapshotArr.get(0,0); // Get the value of array[0] with snap_id = 0, return 5..
from typing import List, Tuple, Dict from poetry_constants import (POEM_LINE, POEM, PHONEMES, PRONUNCIATION_DICT, POETRY_FORM_DESCRIPTION) # ===================== Provided Helper Functions ===================== def transform_string(s: str) -> str: """Return a new string based on s in which all letters have been converted to uppercase and punctuation characters have been stripped from both ends. Inner punctuation is left untouched. >>> transform_string('Birthday!!!') 'BIRTHDAY' >>> transform_string('"Quoted?"') 'QUOTED' >>> transform_string('To be? Or not to be?') 'TO BE? OR NOT TO BE' """ punctuation = """!"'`@$%^&_-+={}|\\/,;:.-?)([]<>*#\n\t\r""" result = s.upper().strip(punctuation) return result def is_vowel_phoneme(phoneme: str) -> bool: """Return True if and only if phoneme is a vowel phoneme. That is, whether phoneme ends in a 0, 1, or 2. Precondition:…
Bishops on a binge def safe_squares_bishops(n, bishops): A generalized n-by-n chessboard has been taken over by some bishops, each represented as a tuple (row, column) of the row and the column of the square the bishop stands on. Same as in the earlier version of this problem with rampaging rooks, the rows and columns are numbered from 0 to n - 1. Unlike a chess rook whose moves are axis-aligned, a chess bishop covers all squares that are on the same diagonal with that bishop arbitrarily far into any of the four diagonal compass directions. Given the board size n and the list of bishops on that board, count the number of safe squares that are not covered by any bishop. To determine whether two squares (r1, c1) and (r2, c2) are reachable from each other in one diagonal move, use abs(r1-r2) == abs(c1-c2) to check whether the horizontal distance between those squares equals their vertical distance, which is both necessary and sufficient for the squares to lie on the same diagonal. This…
#The Iris Dataset import sklearn.datasetsimport matplotlib.pyplot as plt import numpy as np import scipy iris = sklearn.datasets.load_iris() Write a function that takes in an index i and prints out a verbose desciption of the species and measurements for data point i. For example:Data point 5 is of the species setosaIts sepal length (cm) is 5.4Its sepal width (cm) is 3.9Its petal length (cm) is 1.7Its petal width (cm) is 0.4
Double any element's value that is less than controlValue. Ex: If controlValue = 10, then dataPoints = {2, 12, 9, 20} becomes {4, 12, 18, 20}. import java.util.Scanner; public class StudentScores { public static void main (String [] args) { Scanner scnr = new Scanner (System.in); final int NUM_POINTS = 4; int [] dataPoints new int [NUM_POINTS]; int controlValue; int i; controlValue = scnr. nextInt (); for (i = 0; i < dataPoints.length; ++i) { = scnr.nextInt (); dataPoints [i] } /* Your solution goes here * / for (i = 0; i < dataPoints.length; ++i) { System.out.print (dataPoints[i] + %3D " ") ; } System.out.println ();
Design and implement a method to return the index of the smallest value in in arr. Example 1: Input: [11, 4, 9, 2, 25, 36, 49] Output: [3] Explanation: 2 is the smallest value in the array, and it’s index position is 3 (0-based index). Example 2: Input: [1, 4, 9, 2, 25, 36, 49] Output: [0] Explanation: 1 is the smallest value in the array, and it’s index position is 0 (0-based index). Important: You don’t need to test this method in main(). You don’t need to initialize the array. pubilc static int indexOfSmallest(int [] arr)}
int binsearch (int X , int V [] , int n ) { int low , high , mid , i ; low = 0; high = n - 1; for ( i = 0; i < high ; i ++) { if( V[ i ] > V [ i +1]) return -2; } while ( low <= high ) { mid = ( low + high )/2; if ( X < V [ mid ]) high = mid - 1; else if ( X > V [ mid ]) low = mid + 1; else return mid ; } return -1; } This code takes as input a sorted array V of size n, and an integer X, if X exists in the array it will return the index of X, else it will return -1. 1. Draw a CFG for binsearch(). 2. From the CFG, identify a set of entry–exit paths to satisfy the complete statement coverage criterion. 3. Identify additional paths, if necessary, to satisfy the complete branch coverage criterion. 4. For each path identified above, derive their path predicate…
Question-1 Python Machine Learning Question For the Iris data Use classification Models to predict the species of the flowers kNN Classifier Desicion Tree Classifier Random Forest Classifier Try different hyperparameters to improve the scores Visualize your results from sklearn.datasets import load_iris dataset_iris = load_iris() dataset_iris.keys() dict_keys(['data', 'target', 'frame', 'target_names', 'DESCR', 'feature_names', 'filename', 'data_module'])