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- Diagram the cyclization of monosaccharides which leads to the formationof pyran rings. Required: Please show me a correct and step by step process of the diagram and show me the correct drawing of the pyran ring.Draw the step-by-step procedure of linear form (Fischer Projection) of a- D Glucose and B- D Glucose to Haworth. Paste the picture of your drawing below this image anomeric carbon H-č-OH HO-C-H H-C-OH H-C-OH anomers of glucose HO-C-H но-с—н H-C-OH H-Ċ-OH H-C-0- H-C-0- CH,OH CH,OH a-D-glucose B-D-glucoseDraw the Fischer Projection, Haworth and Chair conformation for D-Glucose
- Glucose-1-phosphate has a higher phosphoryl group transferpotential than does glucose-6-phosphate. Review the structures of these molecules and suggest a reason for thisphenomenon.Match the following Class of Proteins with their corresponding Prosthetic Group Components. nucleic acids 1. hemoproteins metal ion 2. lipoproteins phosphate group 3. flavoproteins pigment 4. glycoproteins heme unit 5. phosphoproteins 6. nucleoproteins lipid 5. metalloproteins flavin nucleotides -8 chromoprotein carbohydrateConsider the Haworth projections of f-L-galactose and B-L-glucose shown here. ОН CH OH ОН ОН B-L-galactose enantiomers anomers OH diastereomers epimers ОН CH₂OH OH Which terms describe the relationship between these two sugars? ОН OH B-L-glucose
- A hemoglobin molecule is made up of four polypeptide chains, two alpha chains of 141 amino acid residues each and two beta chains of 146 amino acid residues each. In the complete molecule, four subunits are closely joined, as in a three-dimensional jigsaw puzzle, to form a tetramer. Hemoglobin is showing level of structure O primary secondary tertiary quarternary O pentamericGive the name of two Molecules of Farnesyl Pyrophosphate:Dehalogenase enzymes catalyze the clevage of C-X bonds. One such dehalogenase catalyzes the following reaction. An active site aspartate is thought to carry out the initial nucleophilic attack that expels the chloride. Select the most likely intermediate in the reaction. (Note the stereochemistry. Refer to P11.19 in the textbook if needed.) O O A C D OE -CH₂ H H₂C™ CO₂ H B CO₂ CI N H₂O Cr CO₂ H CO₂ нотум CH3 D CO₂ five N E CH₂
- Consider the positively charged amino acid lysine Lys2+ 21 COOH I H&N-C-H I pH 14 12 10 8 6 4 2 0 CH₂ I CH₂ I CH₂ I CH₂ T NH₂+ 0 Nelson p85 2.18 = 2.18 PK₁ Lys+ COO™ I H₂N-C-H H₂N-C-H ī I -----) 8.95 Lysº 8.95 pK₂ pka carboxyl = 2.19 pkaamino = 9.67 pka sidechain = 4.25 COO™ I CH₂ I CH₂ I CH₂ I CH₂ I NH₂¹ 1.0 2.0 Equivalents of OH added- COO™ I H₂N-C-H I 10.79 1 10.79 pk Isoelectric point Lys CH₂2 I CH₂ I CH₂ I CH₂ T NH₂ 3.0 +H3N NH3+ T CH₂ T CH₂ CH₂ CH₂ -COO™ H Lysine (Lys, K) Physiological pH = 7.4 < pl → Amino acid is positively charged at physiological pH 1. Consider glutamate in its fully protonated form (e.g. in a pH = 1 solution) 1) Draw all the forms of glutamate at various pH 2) Calculate the pl of this amino acid 3) Sketch a titration curve showing pH as a function of added [OH-] and locate the predominant forms of histidine in the curve STEPS: 1. Find the H atoms that can be removed on the molecule 2. Associated a pka value to each removable H. 3. Draw the Aa structure at:…Consider the following blood group A, B, AB and O.What are the sugar(carbohydrate ) content of their glycolipid?The alkaline hydrolysis of pAUGCAGC oligonucleotide produces: O A. Uridine 2'-monophosphate, uridine 3'-monophosphate, cytosine 2'-monophosphate O B. Adenosine 2'-monophosphate, adenosine 3'-monophosphate, adenosine 21,5'-bisphosphate OC. Guanosine 2'-monophosphate, guanosine 3'-monophosphate, cytosine 3'-monophosphate O D. Cytidine 3'-monophosphate, guanosine 2'-monophosphate, adenine 2'-monophosphate O E. Adenine 3,5'-bisphosphate, guanine 2,5'-bisphosphate, uridine 2'-monophosphate O F. Uridine 2'-monophosphate, uridine 3'-monophosphate, guanine 3'-monophosphate