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- Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any “drift†of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…Com X Bb Mas X Mas X Hom X K! Kahx Exan X K! Kah X Mitc X КI Kah X K Kah x K! Kah x Kah x K Kahx C session.masteringchemistry.com/myct/itemView?assignmentProblemID=134214560 Apps New Tab Effect of Salinity on... Sleep Disorders | M... P Philo American Journal ... Zeeshan JBAS Ic Wait for Next Quest... oramge juice Effect c4. A fat sample with combination of acids contain standard hydrochloric acid for blank and sample with 8mL and 5mL respectively. The normality of the standard hydrochloric acid is 0.93N and the weight of the sample is 3 grams. Calculate the saponification value.Trial I Trial II Final reading HCI 26. 40 ml 27.10 ml Initial reading HCI 1.2 ml 1.8 ml Volume of HCl used ? ? Final reading NaOH 33.7 ml 32.8 ml Initial reading NaOH 0.8 mL 0.5 ml Volume of NaOH used ? ? For trial I: Normality of NaOH : 0.25 N Vol. of HCl used = final volume - initial volume Solve for the average Normality of HCI : ? NHCI x VHCI = NNAOH x VNAOH Vol. of NaOH used = final volume - initial volume NNAOH x VNAOH For trial II: NHCI = Vol. of HCl used = final volume - initial volume VHCI Activa Vol. of NaOH used = final volume - initial volume Go to SBased on the given data, what is the λmax of cobalt? 0.1M Cobalt 300 0.451 325 0.467 350 0.584 375 0.629 400 0.694 425 0.673 450 0.541 475 0.433 500 0.423 525 0.327 550 0.264 575 0.245 600 0.233 625 0.211 650 0.189 675 0.187 700 0.165Mon 4:35 PM nnections | Un X * Student Employment | Car X Illinois State University : H X Mind Tap - Cengage Learn X G If a sample of lithium con index.html?deploymentld%3D55750828934189288909969212&elSBN=9781305657571&nbld%3D2199898&snapshotld%3219989. * DTAP Q Search this Use the References to access important values if needed for this question. If a sample of lithium contains 2.50x10 atoms of lithium-7 and 2.00×10³ atoms of lithium-6, what is the percentage of lithium-6 atoms in the sample? Submit Answer 5 question attempts remaining Next Autosaved at 4:32 PM Back0.3414 grams of sample (crushed aspirin tablet) was weighed and dissolved in 25 mL ethanol. This solution was transferred into a 100 mL volumetric flask and filled to the mark with deionized water. 20 mL of the solution was filtered through a 0.22 μm pore filter and 503 μL of the filtered sample solution was diluted so, that the final volume of the solution was 12 mL. This sample solution and calibration solutions with known concentration of acetyl salicylic acid (ASA) were injected (injection volume 20 μL) into a HPLC and the following peak areas were measured (expressed as averages from three separate chromatographic runs): Solution Cal 1 Cal 2 Cal 3 Cal 4 Cal 5 Sample Structure of ASA: C(ASA) (mg/L) 0 OH B 53.5 105.9 140.9 195.4 247.4 Average weight of the tablet was estimated as 591.9 mg. What is the mass of ASA in one tablet? Please give the answer with 4 significant digits. Be sure you present the result with units! Peak area (mA.s) 4995 9953 12941 17271 22179 10467.34. Price the Prescription using the Professional Fee method. Rx Potassium chloride 40 mEq NaCl 30 mEq M. In pp. Tab. No. 20 Sig Dissolve the contents of 1 paper tab in 1 glass of water, taken after breakf - P35.00 Given: Professional Fee each mEq KCI =0.075 g %3D each mEq NaCi = 0.058 g %3D Cost of 100 g KCI P30.0 %3D Cost of 100 g NaCl = P15.00 %3DHelp 100% 4A To Public Health Ch x * HSC 258 - Major Projec X MindTap - Cengage Lea X C The Illustration To TH d%=55750828934189288909969212&elSBN=9781305657571&id=D1061392007&nbld=21... * Q Search th References Use the References to access important values if needed for this question. For the following reaction, 24.7 grams of sulfur dioxide are allowed to react with 9.95 grams of oxygen gas . sulfur dioxide(g) + oxygen(g) → sulfur trioxide(g) What is the maximum mass of sulfur trioxide that can be formed? grams What is the FORMULA for the limiting reagent? grams What mass of the excess reagent remains after the reaction is complete? Submit Answeron You are calibrating a micropipette and measure 100ul of water 5-times and generate the following data set: 0.0996g, 0.1009g, 0.1001g, 0.0989g, 0.0993g. Calculate the % error of your micropipette assuming the density of water is equal to 1.0000g/mL. a. 0.24% b. 2.400% c. 0.2400% d. 0.240%Doard.learn.xythos.prod/579872cf81db6/2987817?X-Blackboard-53-Bucket-blackboard.learn.xythos.prod&X-Blackboard-Expiration= S 1/2 CHEM1407 HF HBr #1) Identify if the following substances are a weak acid, strong acid or neither and write the dissociation equation for the acids LiOH H₂SO3 NH3 HC₂H302 HCIO4 HCIO HF H₂SO4 #2) Identify the following as a monoprotic, diprotic, or triprotic acids H3PO4 HC1O2 HNO3 100% + H₂C₂O4 Homework Ch 16, Sec 6A H Name: 63°F Mostly cloudyASSAY Calibration solutions Calibration solutions of naproxen in the range 5 – 25 μg/mL were prepared. Sample preparation 20 tablets weighing 12.3819 g were crushed to a fine powder. A portion of the powder (145.4 mg) was shaken with approximately 150 mL of acetic acid (0.05 M) for 5 min and then made up to volume in a 250 mL volumetric flask (stock solution). Approximately 50 mL of the stock solution was filtered and a 25 mL aliquot was diluted to 100 mL in a volumetric flask. 10 mL of the resulting solution was further diluted to 100 mL with acetic acid (0.05 M). Analysis The standards and sample solutions were analyzed by HPLC under the following conditions: Column: octadecylsilyl (ODS), 4.6 mmx150 mm, mobile phase: acetonitrile : 0.05 M acetic acid (85:15), flow rate: 1 ml/min, UV detection at 243 nm. Results: A calibration curve of concentration versus peak area was constructed for the standard solutions and gave the straight-line equation: y = 3555.6x + 85, r = 0.9999 The area…SEE MORE QUESTIONS