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- If f(A) = 0.8 and f(a) = 0.2, what is the frequency of AA if the population is at Hardy- Weinberg equilibrium? 0.2 O0.16 O 0.32 0.64 0.8The calculated chi-square value which is 0 is less than the critical value which is 5.991 (under the degree of freedom 2). What is the probability of the computed chi-square value? And is it part of the population in Hardy-Weinberg equilibrium?You repeatedly draw samples ofn= 100 from a population with a mean of 75 and a standard deviation of 4.5. What sample mean corresponds to az-score of 2.00?
- In a population of 2000 individuals, 720 are AA, 960 are Aa, and 320 are aa. Is this population in Hardy-Weinberg equilibrium? Assume any differences greater than 3% (or 0.03) from expected frequencies is significant. O No O More information is needed to answer this question. O YesIf the Chi-squared value for this system is 2.40, is.the population in Hardy-Weinberg equilibrium? Why? (note: the critical values for this test is 3.84). [Select]A population of boreal toads has a current size of 100 and time steps are measured in years. If the instantaneous rate of increase is 0.8 (toads/(toadXtime)), what will the expected population size be after two years? Note: You need to first figure out which equation to use for this problem. O 64 toads O 117 toads O 495 toads O 6400 toads No toads will be left because the instantaneous rate of increase is less than 1.0.
- Which of the following variables from the concept of Hardy Weinberg Equilibrium would you need to calculate for in order to figure out the frequency of the population of carriers in a region? O P^2 Q^2 P*Q[S] (mM) v0 (mM/sec) 6 150 17 250 29 260 40 360 50 350 60 400 72 403 82 425 92 430 103 442 115 455 125 450 Km and Vmax obtained from the Lineweaver-Burk plot and linear regression analysis for the data in Table 2 are 16.9 mM and 503 mM respectively. Compare these values to the values obtained Vmax = 525.3 µM/sec Km = 20.70 µM . Which method, nonlinear regression or linear regression, is more tolerant to an experimental error? Note that lower substrate concentrations, which often have the greater error, have a greater effect on the slope of the line in the Lineweaver-Burk plot.What does it mean when your data/population conforms to Hardy-Weinberg Equilibrium?
- While studying a emerging population of seals, you're asked to determine if the population is in Hardy-Weinberg equilibrium. Given the below data determine the chi square and whether the population is in H-W equilibrium. Choose the closest numerical answer for the chi-square value and either yes or no regarding whether the population is in HWE. AA - 45 Aa - 35 aa - 20 A chi-square critical values table is here (Links to an external site.). Group of answer choices 2.56 6.42 6.20 6.92 No Yes 3.45I'm needing help with part 1 through 3, please The data of Sugar Water and Plain Water: mean # of drops variance degrees of freedom t stat t crit (from the table) plain water 25.3 17.221 38 -4.01 2.0261 sugar water 21.3 21.256 1. Make a statement about t stat in relation to t crit. And what is the p-value? 2. Is there a statistically significant difference between the mean values (mean # of drops) of the sugar and plain water? Give your "yes" or "no" answer and the supporting evidence. 3. Hypothesis: The surface tension of plain water is higher than the surface tension of sugar water. Do these results support or refute the hypothesis about the effect of dissolving salt in water on surface tension?Please Answer problem number 2 Next, use the Hardy-Weinberg equation (p2 + 2pq + q2 = 1) to calculate the expected frequencies of genotypes CGCG , CGCY , and CYCY for a population in Hardy-Weinberg equilibrium.