If I have a function that is one-to-one but not onto (e.g., f(x) = e^x) why does this not contradict the Rank-Nullity Theorem?

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter4: Polynomial And Rational Functions
Section4.2: Polynomial Functions
Problem 96E: What is the purpose of the Intermediate Value Theorem?
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If I have a function that is one-to-one but not onto (e.g., f(x) = e^x) why does this not contradict the Rank-Nullity Theorem?

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