If the Gibbs free energy change for the reaction; Succinate + FAD →Fumarate + FADH2is -40KJ/mol at 37° C. Calculate the ratio of FAD: FADH2 in this condition, if[Succinate]=0.75M and [Fumarate]=0.5M at this condition.Half reactionStandard reduction potential (in volts)Fumarate + 2H + 2 e →Succinate0.031FAD+2H+ + 2e →FADH2-0.219

Biological oxidation-reduction reactions involve the transfer of electrons from one biomolecule,…

Answered: If the Gibbs free energy change for the…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Calculate AG for the below balanced redox reaction as written. You may find a list of standard reduction potentials useful. 3 12 (s) + 2 Al (s) → 61 (aq) + 2 Al3+ (aq) O-4.24 x 102 kJ/mol O-6.48 x 102 kJ/mol O -2.12 x 102 kJ/mol O-1.27 x 103 kJ/mol O-6.37 x 102 kJ/mol
Calculate the standard free energy change for the following reaction: 3-PG + ATP 1,3-BPG + ADP ---> Given the following standard free energies of hydrolysis: ATP = - 31 kJ/mol 1,3-BPG = - 49.6 kJ/mol 18.6 kJ/mol 80.6 kJ/mol -80.6 kJ/mol 18.6 kJ/mol
Inside cells, the AG value for the hydrolysis of ATP to ADP + Pi is approximately -50 kJ/mol (-12 kcal/mol). Calculate the approximate ratio of [ATP] to [ADP][Pi ] in cells at 37°C. AG = AG + RT InKe R= 8.315 x 10³ kJ mol deg T= 298 K Table 15.1 Standard free energies of hydrolysis of some phosphorylated compounds Compound kJ mol- kcal mol- Phosphoenolpyruvate 1,3-Bisphosphoglycerate Creatine phosphate ATP (to ADP) -61.9 -14.8 -49.4 -11.8 -43.1 -10.3 -30.5 - 7.3 - 5.0 Glucose 1-phosphate Pyrophosphate Glucose 6-phosphate -20.9 -19.3 -4.6 -13.8 3.3 Glycerol 3-phosphate - 9.2 2.2 biochemistry
Consider the following equilibrium at 25ºC :Glucose-1-Phosphate Glucose-6-PhophateUsing the equilibrium concentrations of [Glucose-1-Phosphate] = 0.35 M and [Glucose-6-Phosphate] = 1.65 M, calculate BOTH K′eqand Gº′ for this reaction. Is this reaction exergonicor endergonic? R = 8.314 J/K·mol
Consider the following reaction:ATP → AMP + 2 PiCalculate the equilibrium constant (Keq) given the following ΔG°′ values:ATP → AMP + PPi (−32.2 kJ/mol)PPi → 2Pi (−33.5 kJ/mol)
Calculate AG for this reaction under the following conditions: 37°C, pH 7, [Pyruvate] = [CO₂] = 4.0 mM, [OAA] = 2.0 mM, [ATP] = 3.5 mM, [P;] = 5.0 mM, and [ADP] = 1.8 mM. Use 2 signficant figures. AG= i kJ.mol-1 Under these conditions, the reaction is (Tolerance is +/- 2%)
The ΔG°′ for hydrolytically removing a phosphoryl group from ATP is about twice as large as the ΔG°′ for hydrolytically removing a phosphoryl group from AMP (−14 kJ · mol−1). Explain the discrepancy.
A) Calculate the Gibbs free energy change for the following reaction: Fructose diphosphate If the reaction is performed at 27°C and AH is 1,246 calories and AS is 4 calories/K. Is this a spontaneous or non-spontaneous reaction. Why? Is the reaction endergonic or exergonic? DHAP+ Glyceraldehyde phosphate
A bacterial enzyme catalyzes the hydrolysis of maltose as shown in the reaction given below: Maltose + H2O -> 2 glucose If the reaction has a Km of 0.135 mM and a V max of 65 m mol/min. What is the reaction velocity when the concentration of maltose is 1.0 mM?
Given the following coupled reactions: phosphoenolpyruvate + H2O → pyruvate + Pi ΔG°'= -61.9 kJ/mol ATP + H2O → ADP + Pi ΔG°'= -30.5 kJ/mol write the overall reaction, calculate the ΔG°’, and determine if the reaction is exergonic or endergonic. The overall reaction is ______ + _______ → _______ + _________ The overall ΔG°’ is ________ kJ/mol. Therefore, the reaction is _______(exergonic/endergonic)
The decomposition of crystalline N2O5 N2O5(s) → 2NO2(g) + 1/2O2(g) is an example of a reaction that is thermodynamically favored, even though it absorbs heat. At 25 °C we have the following values for the standard state enthalpy and free energy changes of the reaction: ∆H° = +109.6 kJ/mol ∆G° = -30.5 kJ/mol (a) Calculate ∆S ° at 25 °C. (b) Why is the entropy change so favorable for this reaction?
A bacterial enzyme catalyzes the hydrolysis of maltose as shown in the reaction given below: Maltose + H2O -> 2 glucose If the reaction has a Km of 0.135 mM and a V max of 65 umol/min. What is the reaction velocity when the concentration of maltose is 1.0 mM? (Please take note of the units)

SEE MORE QUESTIONS

Recommended textbooks for you

Biochemistry

ISBN:

9781319114671

Author:

Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:

W. H. Freeman

Lehninger Principles of Biochemistry

Biochemistry

ISBN:

9781464126116

Author:

David L. Nelson, Michael M. Cox

Publisher:

W. H. Freeman

Fundamentals of Biochemistry: Life at the Molecul…

Biochemistry

ISBN:

9781118918401

Author:

Donald Voet, Judith G. Voet, Charlotte W. Pratt

Publisher:

WILEY

Biochemistry

ISBN:

9781319114671

Author:

Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:

W. H. Freeman

Lehninger Principles of Biochemistry

Biochemistry

ISBN:

9781464126116

Author:

David L. Nelson, Michael M. Cox

Publisher:

W. H. Freeman

Fundamentals of Biochemistry: Life at the Molecul…

Biochemistry

ISBN:

9781118918401

Author:

Donald Voet, Judith G. Voet, Charlotte W. Pratt

Publisher:

WILEY

Biochemistry

ISBN:

9781305961135

Author:

Mary K. Campbell, Shawn O. Farrell, Owen M. McDougal

Publisher:

Cengage Learning

Biochemistry

ISBN:

9781305577206

Author:

Reginald H. Garrett, Charles M. Grisham

Publisher:

Cengage Learning

Fundamentals of General, Organic, and Biological …

Biochemistry

ISBN:

9780134015187

Author:

John E. McMurry, David S. Ballantine, Carl A. Hoeger, Virginia E. Peterson

Publisher:

PEARSON

SEE MORE TEXTBOOKS