If you perform fatty acid biosynthesis with CO2 labeled with 14C, where does the label end up in a fatty acid?
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- Question 6 Give a diagrammatic representation of fatty acid synthase complex and discuss the regulation of fatty acid synthesis.QUESTION 4 What TYPE of inhibition is observed in the following: S E Competitive Non-competitive Uncompetitive AllostericQUESTION 10 Which one of the following statements does NOT correctly describe the current state of the chymotrypsin-substrate complex below or the next mechanistic step that occurs? s,' G193 S195 NH NH R -NH R-NH HN- Ser-195 His-57 HN Asp-102 OA. This intermediate is part of a nucleophilic acyl substitution reaction. OB. In the next step His-57 protonates Ser-195. O C. In the next step His-57 activates a water molecule. O D. In the next step His-57 protonates the leaving group. OE. In the next step the N-terminal fragment of the original substrate departs.
- Question 2. An enzyme was found to convert Acetyl-coA to an acetyl-cysteine intermediate of the enzyme. The structure of cOA is: H H НО СН; HS — СH2— СH2 — N—C—CH,— CH2—N- С—С—С—CH;—0—Р- 0–CH2 Adenine н CH H H H Phosphopantetheine group of coenzyme A 2-O3PO ОН Draw a plausible chemical mechanism. Where is the acetyl-group in acetyl-coA? What is the reactive group of the protein? The reaction is enhanced at higher pH. How is this consistent with your mechanism? Is covalent catalysis involved?Question:- Two enzymes, acetate kinase and phosphotransacetylase, convert acetate [CH3C(O)O–] and ATP to acetyl phosphate and ADP (acetate kinase reaction) then acetyl phosphate and CoASH (coenzyme A) into acetyl-CoA and inorganic phosphate (Pi ; phosphotransacetylase reaction). What is the ΔG°' for the synthesis of acetyl-CoA from acetate, CoASH, and ATP by this enzyme pair?QUESTION 1 Which of the following concepts in column A best fits the concept in column B. p-Nitrophenyl a-D-Glucoside Action of intracellular a-GLUCOSIDASE + NaHCO3 Boiling cells Tris-pH 5.0 A. Substance that act as molecular mimic of a maltose molecule B. Develops TT-Nitrophenyl into a yellow colour reagent for measurement at 400nm c. Breaks the a-linkages of p-Nitrophenyl a-D-Glucoside, leaving p-Nitrophenyl and a glucose molecule D. Allows transport of p-Nitrophenyl a-D-Glucoside across the membrane E. Stop the reaction and release internal p-Nitrophenyl
- QUESTION 2 Which peptide will most strongly attach to a carboxymethyl ion exchange column at pH 7.4? O N'-Glu-Lys-Arg-Asp-Tyr-C' O N'-Tyr-Arg-Lys-Arg-Gly-C' O N'-Gly-Glu-Gln-Asp-Asp-C' O N'-Val-Ala-Leu-lle-Arg-C' QUESTION 3 Which will be product of transcription from this double-stranded (ds) DNA sequence? 5' - atgttcaaagcctattcg - 3' 3' - tacaagtttcggataagc - 5' O YKFRIS O uacaaguuucggauaagc O auauucaaaaccuauuca Which will be product of transcription from this double-stranded (ds) DNA sequence? 5' - atgttcaaagcctattcg – 3' 3' - tacaagtttcggataagc – 5' O YKFRIS O uacaaguuucggauaagc O auguucaaagccuauucg Ο MFKAYS QUESTION 4 The structure of hemoglobin consists of a 2a and 2B heterotetramer. O quaternary O tertiary O secondary O primaryQuestion 1 and are glycosamines linked to three-carbon acids at the C-1 or C-3 positions, and components of thepolysaccharides of cell higher organisms and bacterial cell walls. Glucosides; galactosides Muramic acid; neuraminic acid O Gluconic acid; glucuronic acid O Sorbitol; ribitolIncorrect Question 5 The active site of a protein has a shape that most nearly fits None of the above Substrates Products Transition state
- Question 7 of 16 ©Mat One way of expressing the rate at which an enzyme can catalyze a reaction is to state its turnover number. The turnover number is the maximum number of substrate molecules that can be acted on by one molecule of enzyme per unit of time. The table gives the turnover number of four representative enzymes. W F2 #m 3 E How many molecules of fumarate can one molecule of fumarase act on in 29.0 min? D fumarate Lactate dehydrogenase lactate fumarate molecules: F3 > Enzyme Ribonuclease Fumarase $ 4 R Urease F F4 % 5 T G B 6 HOLO F5 Substrate Turnover number (per second) RNA 100 800 1000 10.000 Y H & 7 urca F6 U J DELL * 8 CO F7 K ( 9 FB O P ; man Wi F10 [ F11 1 F12 Backspace Enter Insert Print Screen Shift Delete Home Scroll Lock Answer End 8:24 PM 10/15/2023 + PgUp Pause Break PgDn Num Lock 7 Home 4 1 EncQUESTION S Amino acid monomers are grouped into three categories based on their "R" group around the alpha carbon. Which pairing most accurately depicts the reason for the "R" group category? O Polar uncharged R group amino acids have functional groups that are strongly electronegative. O Non polar R group amino acids have hydrocarbon functional groups such as methane. O Polar charged R group amino acids have functional carboxyl and amino functional groupsFatty acid biosynthesis involves what sequence of reactions? Question 17 options: condensation → oxidation → reduction → dehydration condensation → oxidation → oxidation → hydration condensation → reduction → dehydration → reduction condensation → reduction → reduction → dehydration