If you shoot a 10 kg cannonball straight it reaches a height of 600 meters, what was the velocity of the cannonball when it came out of the barrel ?
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- 5. (a) Derive the rocket equation v - Vo = -Vex ln VO m mo Vex In mo m (b) What will be the ratio mfinal/minitial if the rocket engine exhaust velocity is 2 km/s and the final velocity needed is 10 km/s. Take the initial velocity to be zero.Would you care to fire a gun that has a bullet 10 times as massive as the gun? Explain.I am unsure how to solve this problem, how do I do it?
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- (2) The so-called rocket equation is v – vo = Vex ln(mo/m), where v and m are the speed and mass of the rocket at a certain time, vo and mo are the corresponding initial values, and ver is the exhaust speed of the burning fuel relative to the rocket. A certain two-stage rocket carries 70% of its initial mass as fuel. In the first stage, it burns 40% of its fuel. In the second stage, the rocket first ejects the first-stage fuel tank, which has mass 0.2mo, and then burns the rest of its fuel. (a) In terms of ver, what is the final speed of the rocket ? (b) Had all the fuel been burned in a single stage, without ejecting the first stage fuel tank, what would have been the final speed ?39 39 - A 0.100 kg ball is launched directly into the air with an initial velocity of 25 m/s. Find the speed of the ball halfway up to its maximum height? a) 106 m/s B) 62 m/s NS) 11.6 m/s D) 31.25 m/s TO) 5m/sThe momentum of an isolated system is conserved O none of the given choices O only in elastic collisions O only if the objects have the same velocity O in both elastic and inelastic collisions O only in inelastic collisions