Ifx +2y+32 = x2 + 2y2 + 3z2 = x² + 2y3 + 3z3 = 2, and xx +2y2y3 +3z₂Z3 = x3x₁ +2y3v₁ +3Z3Z1 = x₁x₂ + 2y₁y₂ +3Z₁Z2 = Z₁ Z2 Z3 X1 then find the value of x₂ x3 Y₁ Y₂ Y3

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