(ii) Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to calculate the electron affinity of chlorine: Ca(g) Ca²+ (g) 2Cl(g) Ca(s) Ca(g) Cl2(g) Ca²+ (g) Ca(s) + + 2Cl (g) Cl2(g) + 2e- CaCl2(s) CaCl2(s) AHat +190 kJ/mol AHIE = +1730 kJ/mol AHat = +121 kJ/mol AHLE = -2184 kJ/mol AHF = -795 kJ/mol
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- Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to calculate the electron affinity of chlorine: Ca(s) Ca(g) DHat = +190 kJ/mol Ca(g) Ca2+(g) + 2e- DHIE = +1730 kJ/mol Cl2(g) 2Cl(g) DHat = +121 kJ/mol Ca2+(g) + 2Cl-(g) CaCl2(s) DHLE = -2184 kJ/mol Ca(s) + Cl2(g) CaCl2(s) DHF = -795 kJ/mol(ii) Draw the Born-Haber cycle and use the data below for the formation of calcium chloride, to calculate the electron affinity of chlorine: Ca(s) → Ca(g) AHat = +190 kJ/mol Ca(g) > Caz*(g) + 2e¨ AH¡ɛ = +1730 kJ/mol Cl2{g) 2C1(g) AHat = +121 kJ/mol Caz (g) + 2Cl(g) > CaCl2(s) AHLE = -2184 kJ/mol Ca(s) + Cl2(g) –> CaCl2(s) AH; = -795 kJ/molDraw the Born-Haber cycle and use the data below for the formation of calcium chloride, to (ii) calculate the electron affinity of chlorine: DHat = +190 kJ/mol Ca(s) Ca(g) Ca2* (9) 2е- DHJE = +1730 kJ/mol + Ca(g) 2Clg) DHat = +121 kJ/mol Cl2(g) CaCl2(s) DHLE = -2184 kJ/mol Ca2+, 2Cl (g) + *(9) CaCl2(s) DHF = -795 kJ/mol Ca(s) + Cl2(g)
- Use the following data and the Born-Haber cycle to calculate the first ionization energy (ΔH IE1) of K(g) K(s) → K(g) 89 kJ mol-1 Cl(g) + e– → Cl–(g) -349 kJ mol-1 K(s) + ½ Cl2(g) → KCl(s) -437 kJ mol-1 K(g) → K+(g) + e– ΔH IE1 Cl2(g) → 2Cl(g) 244 kJ mol-1 K+(g) + Cl–(g) → KCl(s) -717 kJ mol-1Use the following data and the Born-Haber cycle to calculate the first ionization energy (ΔH IE1) of K(g) K(s) → K(g) 89 kJ mol-1 Cl(g) + e– → Cl–(g) -349 kJ mol-1 K(s) + ½ Cl2(g) → KCl(s) -437 kJ mol-1 K(g) → K+(g) + e– ΔH IE1 Cl2(g) → 2Cl(g) 244 kJ mol-1 K+(g) + Cl–(g) → KCl(s) -717 kJ mol-1 Use the bond energies listed in the table below to estimate the standard enthalpy of the reaction: CCl3CHCl2(g) + 2HF(g) → CCl3CHF2(g) + 2HCl(g) C – H 412 kJ mol-1 C – C 348 kJ mol-1 C – Cl 338 kJ mol-1 H – Cl 431 kJ mol-1 C – F 484 kJ mol-1 H – F 565 kJ mol-1Use the data given below to construct a Born-Haber cycle to determine the electron affinity of Br. ΔH°(kJ mol-1) K(s) → K(g) 89 K(g) → K⁺(g) + e⁻ 419 Br2(l) → 2Br(g) 193 K(s) + ½Br2(g) → KBr (s) -394 KBr(s) → K⁺(g) + Br⁻(g) 674 A) -885 kJ B) -464 kJ C) +367 kJ D) -325 kJ E) +246 kJ
- Consider the following data for indium: atomic mass electronegativity ionization energy 114.82 electron affinity 28.9 heat of fusion 1.78 558.3 mol 3.26 kJ mol kJ mol kJ mol Does the following reaction absorb or release energy? (1) In (g) + e In* (g) Is it possible to calculate the amount of energy absorbed or released by reaction (1) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (1): Does the following reaction absorb or release energy? (2) In (g) + e In (g) Is it possible to calculate the amount of energy absorbed or released by reaction (2) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (2): O release O absorb O Can't be decided with the data given. O yes O no ☐kJ/mol O release O absorb O Can't be decided with the data given. O yes O no kJ/molWhich of the following reactions represents an electron gain energy that would be positive (i.e. endothermic). S(g) → S+(g) + e- Cl(g) → Cl+(g) + e- Kr(g) + e- → Kr-(g) S(g) + e- → S-(g) Kr(g) → Kr+(g)+ e- Cl(g) + e- →Cl-(g)Which of the following reactions represents an electron gain energy that would be positive (i.e. endothermic). O(g) → O+(g) + e- Ne(g) + e- → Ne-(g) O(g) + e- → O-(g) I(g) → I+(g) + e- I(g) + e- → I-(g) Ne(g) → Ne+(g)+ e- fast plz
- Using the following data, draw the Born Haber cycle for the formation of hypothetical compound of MX(s) from its elements. Using the Born Haber cycle, calculate the electron affinity of X. M (s) → M (g) ∆Hº = 77 kJ mol-1M (g) → M+ (g) + e- ∆Hº = 433 kJ mol-1X2 (g) → 2X (g) ∆Hº = 129 kJ mol-1M (s) + ½ X2(g) → MX(s) ∆Hº = -530 kJ mol-1M+ (g) + X-(g) → MX (s) ∆Hº = -760 kJ mol-1Given the following information, construct a Born-Haber cycle to calculate the lattice energy of CrCl₂I(s): Net energy change for the formation of CrCl₂I(s) = -420 kJ/mol Bond dissociation energy for I2(g) = +243 kJ/mol Bond dissociation energy for Cl2(g) for Cl2(g) for 12(g) = +151 kJ/mol Heat of sublimation for I2(s) = +62 kJ/mol Heat of sublimation for Cr(s) = +397 kJ/mol = E₁₁ for Cr(g) = 652 kJ/mol E₁₂ for Cr(g) == 1588 kJ/mol E₁3 for Cr(g) = 2882 kJ/mol Eea for Cl(g)=-349 kJ/mol === Eea for I(g) = -295 kJ/mol1) Calculate the lattice energy for NaCl(s) using a Born-Haber cycle and the following information: NaCl(s) → Nat(g) + Cl-(g) Na(s) + 1/2 C12(g) → NaCl(s) Na(s) → Na(g) Na(g) → Na+(g) + e- 1/2 C12(g) → Cl(g) Cl(g) + e- → Cl-(g) ? -411.0 kJ/mol +107.3 kJ/mol +495.8 kJ/mol +121.7 kJ/mol -348.6 kJ/mol