In a random sample of 200 people, 154 said they watched educational television. We wish to construct a 98% confidence interval for the true proportion of people who watch educational television. a) What is the critical value we would use for this confidence interval? b) What is the 989% confidence interval for the true proportion of people who watch educational television?

Q: what would be the 90% confidence interval of the true proportion of young adults who have received…

A: Given that sample size is n = 190 And the sample proportion is 70% = 0.7 At 90% confidence level,…

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: In this question, It has been given that Margin of error = 0.05 and level of significance = 0.005.…

Q: In response to a recent GSS survey on whether the Government should impose strict laws to prohibit…

A: Solution: Let X be the number of subjects said “yes” and n be the sample number of subjects. From…

Q: What is the relationship between confidence intervals and hypothesis testing? When testing Ho: μ =…

A: Given: Confidence interval=90% Level of significance, a= 1-0.90=0.10

Q: The confidence interval was (41%, 45%) What was the margin of error? +/- % What was the summary…

A:

Q: In a random sample of 145 UNO students, we find that 53% have attended a Maverick hockey game at…

A:

Q: We surveyed 53 people in an attempt to determine the proportion of Americans who lease a vehicle. 13…

A: The proportion of sample Americans who lease a vehicle is, Thus, the proportion of sample Americans…

Q: In a random sample of 100 voters in a school district, 40 of them stated they were in favor of the…

A: Solution: Let X be the number of voters stated they were in favor of the school district bond…

Q: In a study of 200 accidents that required treatment in an emergency room, 80 occurred at work. Find…

A: Obtain the 90% confidence interval for the true proportion of accidents that occurred at work. The…

Q: 10 Life insurance policies in a sample of 200 taken out of 50,000 were found to be insured for less…

A:

Q: A university dean is interested in determining the proportion of students who receive some financial…

A: The point estimate=p^=118200=0.59n=sample size= 200z=critical value of 95% confidence…

Q: In a recent survey of 200 households, 172 had central air conditioning.  Find the 85% confidence…

A: Given that In a recent survey of 200 households, 172 had central air conditioning That is…

Q: 11) In a Gallup poll, 1011 adults were asked if they consume alcoholic beverages and 64% of them…

A: (11) Obtain the 90% confidence interval estimate of the proportion of all adults who consume…

Q: Out of 1,500 licensed drivers, 900 admitted that they do not like to drive at night. What is the 92%…

A: Given Information:  Total Number of drivers = 1500  Number of drivers that do not like to drive at…

Q: In a recent poll, 560 people were asked if they liked dogs, and 22% said they did. Find the margin…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: Based on a sample of approximately 600 nonsmokers and 200 smokers, estimate the true difference…

A:

Q: n a survey of 2480 golfers, 372 said they were left-handed. Construct a 92% confidence interval for…

A: The given data is appropriate for single proportion confidence interval . because it is a large…

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A:

Q: Of 380 randomly selected medical​ students, 21 said that they planned to work in a rural community.…

A: Given that 380 randomly selected medical​ students, 21 said that they planned to work in a rural…

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A:

Q: What is the margin of error for a 90% confidence interval?

A: It is given that Sample size n = 850 Number of residents support property tax, X = 410 The critical…

Q: in a survey of 2230 adults, 57% thinks that land travel through a tourist bus is much more reliable…

A: Given,sample size(n)=2230sample proportion(p^)=0.57α=1-0.95=0.05α2=0.025Z0.025=1.96       (from…

Q: In the Framingham Offspring study 3630 subjects were on anti-hypertensive medication out of 4657…

A: Note: Hi, thank you for the question. As per our company guideline we are supposed to answer only…

Q: In a recent polI, 200 people were asked if they liked dogs, and 15% said they did. Find the margin…

A: From the provided information, Sample size (n) = 200 15% people said they like dogs that is p̂ =…

Q: in a recent poll, 220 people were asked if they liked dogs, and 36% said they did . find the margin…

A:

Q: Of 254 randomly selected medical students, 25 said that they planned to work in a rural community.…

A: It is given that, the number of students said that they planned to work in natural community   (x)…

Q: What does the 95% represent in a 95% confidence interval

A: Solution CI=95%

Q: When 328 college students are randomly selected and surveyed, it is found that 122 own a car. Find…

A: We want to find 95% CI for population proportion (p)

Q: Out of 500 people sampled, 455 had kids. The best point estimate for p is . The margin of error…

A:

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Given that, X = 118 N = 200 99% confidence level

Q: in a random sample of 192 college students, 129 had part-time jobs. Find the margin of error for the…

A:

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: Obtain the sample size of a no preliminary estimate for p. The formula of sample size is, Here,…

Q: In a random sample of 184 college students, 97 had part-time jobs. Find the margin of error for the…

A: Given : Sample Size, n = 184 Number of successes, x = 97 confidence level,c=0.99

Q: In a survey of 2480 golfers, 372 said they were left-handed. Construct a 92% confidence interval for…

A: GIVEN DATA : Total number of golfers are 2480, Number of left handed golfer are 372        TO FIND :…

Q: 1. In a poll of 2,500 likely voters, 966 say that the Philippines spend too little on education.…

A:

Q: Construct a 95% confidence interval for the population proportion of students who graduate within…

A: The sample size is n = 400 And the number of students who graduate within six years, X = 108 The…

Q: n 2013, the Gallup poll asked 1,039 American adults if they believe there was a conspiracy in the…

A: Given data, n=1039 x=634 sample proportion p=x/n =634/1039 =0.61   z-value at 90% confidence is…

Q: In a sample of 95 recommendations, it is found that 56% of them made money. Determine the upper…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: In a recent poll of 200 randomly selected adults in the U.S., 130 were registered to vote. a) What…

A: Hello, thanks for your question. Since you have posted a question with multiple sub-parts, we will…

Q: b. Construct a 90% confidence interval for the percentage of all judges who are in favor of the…

A: a. A random sample of 15 judges and asked them whether or not they favor the death penalty in which…

Q: university dean is interested in determining the proportion of students who receive some sort of…

A:

Q: A college administrator is interested in determining the proportion of students who receive some…

A:

Q: Construct a 99% confidence interval for the true proportion of all car license applications that…

A: Given Information:x=25n=155c=99%=0.99

Q: If a retailer would like to estimate the proportion of their customers who bought an item after…

A: Solution: 3. From the given information, confidence level is 0.90 and E=0.03.

Q: According to a poll taken in a certain​ country, when adults were asked whether they were​ thriving,…

A: Sample size (n) = 439 240 of them said that they were struggling that is x = 240. The sample…

Q: A study of 150 randomly selected accidents that involved trips to the emergency room found that 36%…

A: Given 99% confidence level, significance level α=1-0.99=0.01

Q: Construct a 99% confidence interval for the proportion of all motorbike license applications that…

A: We want to find the 99% confidence interval  Given  X=20 , n=175

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Here we need to construct a 95% confidence interval for the population proportion. Here the sample…

Q: What would be the standard error in computing a confidence interval for the difference of…

A: It is given that For population 1, sample size n1 = 49, sample proportion = 0.682 For population 2,…

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: Given dataError = 2.5% = 0.025Confidence level = 0.995Significance level = α=1-0.995=0.005

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.