In an emergency situation, a person with a broken forearm ties a strap from his hand to clip on his shoulder as in the figure below. His 1.60-kg forearm remains in a horizontal position and the strap makes an angle of 0 = 53.5° with the horizontal. Assume the forearm is uniform, has a length of e = 0.324 m, assume the biceps muscle is relaxed, and ignore the mass and length of th hand. (a) Find the tension in the strap. N (b) Find the components of the reaction force exerted by the humerus on the forearm. (Assume the positive x-direction is to the right and the positive y-direction is upward.) Ry = N Ry =

In an emergency situation, a person with a broken forearm ties a strap from his hand to clip on his shoulder as in the figure below. His 1.60-kg forearm remains in a horizontal position and the strap makes an angle of 0 = 53.5° with the horizontal. Assume the forearm is uniform, has a length of e = 0.324 m, assume the biceps muscle is relaxed, and ignore the mass and length of th hand. (a) Find the tension in the strap. N (b) Find the components of the reaction force exerted by the humerus on the forearm. (Assume the positive x-direction is to the right and the positive y-direction is upward.) Ry = N Ry =

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter12: Static Equilibrium And Elasticity

Section: Chapter Questions

Problem 13CQ: Note: Unless stated otherwise, the weights of the wires, rods, and other elements are assumed to be...

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In an emergency situation, a person with a broken forearm ties a strap from his hand to clip on his shoulder as in the figure below. His 1.60-kg forearm remains in a horizontal position and the strap makes an angle of ? = 45.0° with the horizontal. Assume the forearm is uniform, has a length of ℓ = 0.342 m, assume the biceps muscle is relaxed, and ignore the mass and length of the hand. (a) Find the tension in the strap. N(b) Find the components of the reaction force exerted by the humerus on the forearm. (Assume the positive x-direction is to the right and the positive y-direction is upward.) Rx = N Ry = N
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Find the force exerted by the biceps muscle in holding a 1.00-L milk carton (weight 9.90 N) with the forearm parallel to the floor. Assume that the hand is 35.0 cm from the elbow and that the upper arm is 30.0 cm long. The elbow is bent at a right angle, and one tendon of the biceps is attached to the forearm at a position 5.00 cm from the elbow, while the other tendon is attached at 30.0 cm from the elbow. The weight of the forearm and the empty hand is 327 N, and the center of gravity of the forearm with hand is at a distance of 16.5 cm from the elbow. MILK 30.0 cm MILK CG 30.0 cm 9.90N 5.00 cm HN -16.5 cm- CG 9.90N 35.0 cm where H = 32.7. 5.00 cm HN -16.5 cm- 35.0 cm where H-327.
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In an emergency situation, a person with a broken forearm ties a strap from his hand to clip on his shoulder as in the figure below. His 1.60-kg forearm remains in a horizontal position and the strap makes an angle of ? = 47.0° with the horizontal. Assume the forearm is uniform, has a length of ℓ = 0.332 m, assume the biceps muscle is relaxed, and ignore the mass and length of the hand. A person with a broken left forearm faces out of the page. His left forearm is approximately horizontal, and a strap extends from a clip on his right shoulder to a position on his left arm that is a distance ℓ from the elbow. The strap is at an angle ? above the forearm. A force vector R acts up and to the right on the left forearm at a location just left of the elbow. (a) Find the tension in the strap. N(b) Find the components of the reaction force exerted by the humerus on the forearm. (Assume the positive x-direction is to the right and the positive y-direction is upward.) Rx = N Ry= N
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