In the figure below, a spider is resting after starting to spin its web. The gravitational force on the spider is 0.170 N on the junction of the three strands of silk. The junction is supported by different tension forces in the two strands above it so that the resultant force on the junction is zero. The two sloping strands are perpendicular, and we have chosen the x and y directions to be along them. The tension T, is 0.111 N. T. T, (a) Find the tension T. N. (b) Find the angle the x axis makes with the horizontal. (c) Find the angle the y axis makes with the horizontal.

In the figure below, a spider is resting after starting to spin its web. The gravitational force on the spider is 0.170 N on the junction of the three strands of silk. The junction is supported by different tension forces in the two strands above it so that the resultant force on the junction is zero. The two sloping strands are perpendicular, and we have chosen the x and y directions to be along them. The tension T, is 0.111 N. T. T, (a) Find the tension T. N. (b) Find the angle the x axis makes with the horizontal. (c) Find the angle the y axis makes with the horizontal.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter4: The Laws Of Motion

Section: Chapter Questions

Problem 23P: A bag of cement weighing 325 N hangs in equilibrium from three wires as suggested in Figure P4.23....

See similar textbooks

Similar questions

A 10.0 kg mass is at rest on a board inclined at an angle of 30.0o above the horizontal. The mass is held in place by the combination of static friction and the 10.6 N tension in a cord attached to the mass on the uphill side, and running parallel to the board. Find the coefficient of static friction (s) between the mass and the board.
Two masses mA =9.3kg and mB=6.1kg are on inclines and are connected together by a string as shown in the figure. The angles theta subscript A=700 and theta subscript B = 360 . In the absence of the friction, the force F is required to pull the masses at a constant velocity up the fixed inclines. The force F is now removed. What is the magnitude of the acceleration of the two blocks? Take g =9.81 m/s2, and express your answer using two decimal places.
The cable AB has a mass of 0.5 kg/m and makes an angle of 15° with the horizontal at point A. Calculate the tension TB and the angle OB. ans: 118 N, 52.8° =15° 12 m B eB IB 9 m
Logs weighing 1.3 kg and 2.2 kg lie on a flat surface and are connected by a rope that breaks at a force of 20 N. The coefficient of friction between the lighter log and the base is 0.50, and between the heavier log and the base 0.30. With what maximum force can we pull the lighter log so that the string does not break?
A patient with a broken tibia has the lower half of his leg suspended horizontally by a cable attached to the center of his foot. The tension in the cable needs to exert a force of F, = 25 N horizontally for traction and F, = 30 N vertically upward to support the leg. Find the magnitude of the tension in the cable. Hint: Put the center of the patient's foot at the origin of the xy-plane. Pulley F₂ x F₁ (Give your answer to one decimal place. Use symbolic notation and fractions where needed.) Flension N
A man weighing 400N climbs up a ladder 5 meters long. The ladder initially rests against a frictionless vertical wall and is at 58° above a rough floor with static friction coefficient of 0.25. determine the location of the man that will cause the ladder to slide down. What is the magnitude and direction of the net force acting on the ladder at the floor? FIND: location of man to cause sliding measured along the ladder (in meters) magnitude of the Net Force on the ladder at the wall (in Newton) angle and direction of the Net force on the ladder at the wall (degrees and N-E-W-S)) Magnitude of the Net force on the ladder at the floor(in Newton) angle and direction of the Net force on the ladder at the floor(degrees and N-E-W-S))
Zoologists have studied the mechanics of locust jumping. When a locust jumps, as depicted in the figure, the resultant force R exerted by the hind legs is the sum of two forces. The first force W acts directly downward to support the locust's weight, which is about 0.02 newton. The second force F is for the takeoff; its magnitude is about 0.29 newton, and the direction makes an angle of 55° with the horizontal. W 55° Find the magnitude of the resultant force R = F + W. (Use decimal notation. Give your answer to three decimal places.) magnitude of resultant force R: newton
A 5.0kg crate is tasting on a horizontal plank. The coefficient of static friction is 0.50. You raise one end of the plank slowly. What is the maximum angle (with horizontal) you can go without the crate sliding down the incline?
Due to a jaw injury, a patient must wear a strap that produces a net upward force of 5.00 N on his chin. The tension is the same throughout the strap. To what tension must the strap be adjusted to provide the necessary upward force?
A sailor is being rescued using a boatswain's chair that is suspended from a pulley that can roll freely on the support cable ACB and is pulled at a constant speed by cable CD. Knowing that a 30° and B 10° and that the combined weight of the boatswain's chair and the sailor is 900 N, determine the tension (a) in the support cable ACB, (b) in the traction cable CD. B.
Using a rope that will snap if the tension in it exceeds 387 N, you need to lower a bundle of old roofing material weighing 449 N from a point 6.1 m above the ground. Obviously if you hang the bundle on the rope, it will snap. So, you allow the bundle to accelerate downward. (a)What magnitude of the bundle’s acceleration will put the rope on the verge of snapping? (b) At that acceleration, with what speed would the bundle hit the ground?
A picture frame hung against a wall is suspended by two wires attached to its upper corners. If the two wires make the same angle with the vertical, what must this angle be if the tension in each wire is equal to 0.75 of the weight of the frame? (Ignore any friction between the wall and the picture frame.)