In the following reaction, determine whether the alkyne has been oxidized, reduced, or neither. (Hint: First look at each carbon atom separately and then look at the net change the alkyne as a whole.) Try to determine the answer without calculating oxidation states and then use the calculations to see if your intuition was correct. H2SO4, H2O H9SO4 O The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has also been oxidized. Overall, the alkyne has been oxidized. The first carbon atom (with two added bonds to 0) has been reduced and the second carbon atom (with two added bonds to H) has also been reduced. Overall, the alkyne has been reduced. The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has been reduced. Overall, the alkyne doe not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized. The first carbon atom (with two added bonds to O) has been reduced and the second carbon atom (with two added bonds to H) has been oxidized. Overall, the alkyne doe not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized.
In the following reaction, determine whether the alkyne has been oxidized, reduced, or neither. (Hint: First look at each carbon atom separately and then look at the net change the alkyne as a whole.) Try to determine the answer without calculating oxidation states and then use the calculations to see if your intuition was correct. H2SO4, H2O H9SO4 O The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has also been oxidized. Overall, the alkyne has been oxidized. The first carbon atom (with two added bonds to 0) has been reduced and the second carbon atom (with two added bonds to H) has also been reduced. Overall, the alkyne has been reduced. The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has been reduced. Overall, the alkyne doe not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized. The first carbon atom (with two added bonds to O) has been reduced and the second carbon atom (with two added bonds to H) has been oxidized. Overall, the alkyne doe not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized.
World of Chemistry, 3rd edition
3rd Edition
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Chapter20: Organic Chemistry
Section: Chapter Questions
Problem 4STP
Related questions
Question
Transcribed Image Text:In the following reaction, determine whether the alkyne has been oxidized, reduced, or neither. (Hint: First look at each carbon atom separately and then look at the net change for
the alkyne as a whole.) Try to determine the answer without calculating oxidation states and then use the calculations to see if your intuition was correct.
H2SO4, H2O
H9SO4
The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has also been oxidized. Overall, the alkyne
has been oxidized.
The first carbon atom (with two added bonds to O) has been reduced and the second carbon atom (with two added bonds to H) has also been reduced. Overall, the alkyne
has been reduced.
The first carbon atom (with two added bonds to O) has been oxidized and the second carbon atom (with two added bonds to H) has been reduced. Overall, the alkyne does
not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized.
The first carbon atom (with two added bonds to O) has been reduced and the second carbon atom (with two added bonds to H) has been oxidized. Overall, the alkyne does
not undergo a net change in oxidation state and is, therefore, neither reduced nor oxidized.
Expert Solution
Step 1
In the above reaction, Alkyne is being converted to ketone upon hydration with aqueous acid(H2SO4).
The addition of a hydroxyl group to an alkyne causes tautomerization which forms carbonyl. Markovnikov addition of a hydroxyl group to an alkyne to form ketone.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
World of Chemistry, 3rd edition
Chemistry
ISBN:
9781133109655
Author:
Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:
Brooks / Cole / Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
World of Chemistry, 3rd edition
Chemistry
ISBN:
9781133109655
Author:
Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:
Brooks / Cole / Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning
Chemistry for Today: General, Organic, and Bioche…
Chemistry
ISBN:
9781305960060
Author:
Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:
Cengage Learning