In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A = î +ĵ +R and an adjacent C-H bond is at the direction B=î--R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 1.06i + 0.8j + 1.03k B = 1i + -0.92j + -0.95k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.

Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter42: Molecules And Solids
Section: Chapter Questions
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In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. 

In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at
the center. If one of the C-H is in the direction of
A =î +Î+k
and an adjacent C-H bond is at the direction
B=î-Î- R.
results to an angular bond of approximately 109° for a static frozen molecule.
However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its
bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be
A = 1.06i + 0.8j + 1.03k
B = 1i + -0.92j + -0.95k
What is the angle (in degrees) between the bonds based on this new data?
Note: Only 1% of error is permitted for the correct answer.
Transcribed Image Text:In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A =î +Î+k and an adjacent C-H bond is at the direction B=î-Î- R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 1.06i + 0.8j + 1.03k B = 1i + -0.92j + -0.95k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.
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