What did i do wrong? DBA83.07'Numbers represent BS and FS observationsElevation of BM 13 is Unknown. Calculate an elevation and apply anadjustment based on the level loop performed.4.50701.32BM 10instrument79.01'instrument66.51'TP 1TP 354.87'8.89'4instrumentinstrument7.10'310.00'SIZEBTP 225.92'instrument8.67'BM 13SCALE: 1":60' SHEET 1 OF 11DCBA IncorrectQuestion 5Based on the level loop and calculationsIf the adjustment is proportional to the number of setups; what is the adjustment applied to BM_13's calculated elevation?A plus or minus sign must be placed in front of your answer - example: +0.03 or -0.03; round your answer to 2 decimal places.+0.01

Height of Instrument, HI = Elevation + BS Elevation = HI - F.S BS = Backsight FS = Foresight

Incorrect Question 5 Based on the level loop and calculations If the adjustment is proportional to the number of setups; what is the adjustment applied to BM_13's calculated elevation? A plus or minus sign must be placed in front of your answer - example: +0.03 or -0.03; round your answer to 2 decimal places. +0.01

Incorrect Question 5 Based on the level loop and calculations If the adjustment is proportional to the number of setups; what is the adjustment applied to BM_13's calculated elevation? A plus or minus sign must be placed in front of your answer - example: +0.03 or -0.03; round your answer to 2 decimal places. +0.01

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Q3: A: Draw the diagram of traverse classification. B: In closed traverse ABCD. The partial coordinates were known as shown below. Determine its area by DMD method. 04 N Dofland OWODY dienstl it with (nm) dinostim Mem. AB BC CD DA ΔΧ 40 -80 -50 AY 60 100 -70
B. Double-Rodded Leveling 3. Complete differential level notes for the information shown and perform the customary arithmetic check. STATION BS HI FS STATION 1.722 BM1 127.378 m 1.722 ΤΡΙΗ 2.623 1.382 TP1L 2.789 1.522 TP2 H 3.089 0.899 TP2 L 3.214 0.714 ТРЗ Н 1.521 2.452 TP3 L 1.632 2.678 ТРА Н 2.333 1.113 TP4 L 2.589 1.523 TP5 H 0.667 2.877 TP5 L 0.986 2.543 3.521 BM2 3.214
Meet - nzw-pimo-rw anuwwlPx-a_a7HdrtDNnmaFDF2GGA/formResponse none of the above. O To establish a new benchmark on point Busing a levelling instrument. The work had been done between B.M1 and B.M2 to the required point B, and the observations were recorded as in the tables below. Calculate the best value *of elevation for point B B.M1 B B.M2 B BS Point B.M1 T. P1 BS FS 3.305 Remarks RL-34.585 FS 0.405 4.24 3.35 Point Remarks B 30.06 0.672 1.825 2.485 3.315 1.23S 3.715 T. P4 T. PS B.M2 1.795 A 4.01 3.485 Т. Р2 T. P3 3.315 2.78 RL=42.093 B 39.97m 41.97m 46.97m 45.98m O 44.37m O 40.95m O * Reciprocal ranging is employed when one end of a line is inaccessible. O the ends of the line are not visible even from intermediate points. O both the ends are inaccessible. the two ends of a line are not intervisible,O O O O O O O O O O OC
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On the drawing below, the virtual condition of the 4 holes is? O .450 .375 O.395 O .020 D O .430 Ø3.000 .020 0 10 45° 4X Ø.395-.430 Ø.500-.510 Ø.020MABMCM +0.010M ADM Ø2.000 .375-.395 4.000MABM C A 0.005MA B
Given the data shown: What is distance AB? 1. What is distance BC? a. 13.21 c. 12.03b. 15.92 d. 17.52 2. Find the DMD for side AB. a. -7.85 c. -5.99b. -6.51 d. -8.55 3. Find the DMD for side BC. a. -1.86 c. -0.96b. -2.02 d. -1.75 4. Find the DMD for side CD.a. 85.65 c. 82.40b. 72.05 d. 80.66 5. Find the DMD for side DA.a. 75.65 c. 73.56b. 74.03 d. 72.76 6. Find the area using DMD Method.a. 1215.98 c. 1449.66b. 1625.31 d. 1315.22
f A 11:- docx.js The following consecutive reading were taken with a level and 4m leveling staff ground at common interval of 30m as 0.725 on A,0.935,2.845,3.745,3.935,0.965,1.135,1.785,2.625,3.845,0.965,1.575 and 2.015 on B. The elevation of point A is 220.50m. Makeup level book page, apply usual check and calculate the reduced levels of points. Also calculate the gradient of line AB. II >
Q1 (a) Q1(b) RL TBM A RL TBM B RL TBM A RL TBM B AAA.AAA BBB.BBB ААА.АAА ВВB.ВBB 135.975 134.665 135.475 134.165 Q1. Table Q1 shows the levelling data obtained from field observations between two temporary benchmarks namely TBM 1 and TBM 2, respectively. Where, the total levelling distance between TBM 1 and TBM 2 is 250 metres. As a junior site civil engineer at the construction site, you have been assigned by a senior site civil engineer to finalise and evaluate the levelling data to ensure the levelling work complies with the levelling standard and procedures. Table Q1 Intermediate Backsight Foresight Remarks Sight 1.592 TBM 1 RL= AAA.AAA m 1.379 Point 1 1.384 Point 2 1.406 Point 3 1.675 2.052 CP1 1.354 1.704 СР2 1.320 0.907 СРЗ 0.940 1.315 СР4 0.832 1.507 CP5 -2.938 Soffit 1 -2.833 Soffit 2 -2.717 Soffit 3 1.546 TBM 2 RL=BBB.BBB m a) Finalise the levelling calculation using rise and fall method, i accuracy check, levelling misclosure and final reduced level for all observed points.…
Q - The subsequent readings were curious about dumpy level with four.zero m leveling team of workers and 20.0 m c program languageperiod. 1.755, 2.505, 3.050, 3.950, 1.750, 2.355, 3.a hundred, three.805, zero.905, 2.0.5 and 3.250. If R.L of first point is 15.zero m. Calculate the R.L of different points by way of H.I approach.
HM 36 Q.3 A level circuit is shown in figure. The survey, needed for local engineering project, commenced at BM 35, the elevation of new benchmarks 36, 37, 38 and 39 were determined, and then the level survey was looped back to BM 35, the point of commencement. Fined the adjusted new BMs. ВМ 35 Elevation(m) 119.010(fixed) 35 36 37 38 39 35 123.342 118.206 118.451 120.491 118.933 09 km. DM 35 O8 km DBM 37 08 km 08 km BM 39 BM 38 0.7 km
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1) Find, the unknowns ("aaa" through "ggg") in the table of dlosed traverse starting from BM and ending with BM BS - Backsight FS = Foresight IS = Intermediate Sight (height of equipment) RL = Reduced Level ERR= Error FS BS 1.672 0.837 IS Rise Fall RL Remarks 93.827 BM 1.245 "bbb" CP1 CP 2 "aaa" 1.526 "eee" "ece" 0.689 93.565 CP 3 BM 0.719 94.284 „PPP. 1.750 0.454 143 5.700 ERR 1/146 0.003 0.003 0.003