Initial speed = 2.92 m/sMaximum Height = 11.1 cmRange (Trial 1) = 0.77 mRange (Trial 2) = 0.686 mRange (Trial 3) = 0.677 m t what angle in (A) was the ball projected? • Initial speed = 2.92 m/s• Maximum Height = 11.1 cmRange (Trial 1) = 0.77 m• Range (Trial 2) = 0.686 mRange (Trial 3) = 0.677 mMotion of Projectile on a Level SurfaceInitial Speed Maximum(m/s)ProjectionRange (m)Angle (°)Trial 1Trial 2Trial 3 AverageHeight (cm)(A)(B)At what angle in (A) was the ball projected?O 30.3°O 12.8°O 74.5°O48.2°

Name: Initial speed = 2.92 m/sMaximum Height = 11.1 cmRange (Trial 1) = 0.77
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Description: Initial speed = 2.92 m/sMaximum Height = 11.1 cmRange (Trial 1) = 0.77 mRange (Trial 2) = 0.686 mRange (Trial 3) = 0.677 m t what angle in (A) was the bal

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Initial speed = 2.92 m/s Maximum Height = 11.1 cm Range (Trial 1) = 0.77 m Range (Trial 2) = 0.686 m Range (Trial 3) = 0.677 m t what angle in (A) was the ball projected?

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter2: Kinematics

Section: Chapter Questions

Problem 1CQ: Give an example in which there are clear distinctions among distance traveled, displacement, and...

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