(Integer) Bit Operators. Write a program that takes begin and end values and prints out a decimal, binary, octal, hexadecimal chart like below. If any of the characters are printable ASCII characters, then print those, too. If none is, you may omit the ASCII column header.
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(Integer) Bit Operators. Write a
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- Complete the code as below mentioned. Write all(Python matplotlib or seaborn) CPU Usage We have the hourly average CPU usage for a worker's computer over the course of a week. Each row of data represents a day of the week starting with Monday. Each column of data is an hour in the day starting with 0 being midnight. Create a chart that shows the CPU usage over the week. You should be able to answer the following questions using the chart: When does the worker typically take lunch? Did the worker do work on the weekend? On which weekday did the worker start working on their computer at the latest hour? cpu_usage = [ [2, 2, 4, 2, 4, 1, 1, 4, 4, 12, 22, 23, 45, 9, 33, 56, 23, 40, 21, 6, 6, 2, 2, 3], # Monday [1, 2, 3, 2, 3, 2, 3, 2, 7, 22, 45, 44, 33, 9, 23, 19, 33, 56, 12, 2, 3, 1, 2, 2], # Tuesday [2, 3, 1, 2, 4, 4, 2, 2, 1, 2, 5, 31, 54, 7, 6, 34, 68, 34, 49, 6, 6, 2, 2, 3], # Wednesday [1, 2, 3, 2, 4, 1, 2, 4, 1, 17, 24, 18, 41, 3, 44, 42, 12, 36, 41, 2, 2, 4, 2, 4], # Thursday [4, 1, 2, 2, 3, 2, 5, 1, 2, 12, 33, 27, 43, 8,…Find the error in the following code
- *Please help in javascript* Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255. Thus (255, 0, 0) is bright red, (130, 0, 130) is a medium purple, (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (In other words, equal amounts of red, green, blue yield gray). Given values for red, green, and blue, remove the gray part. Ex: If the input is: 130 50 130 the output is: 80 0 80 import java.util.Scanner; public class LabProgram {public static void main(String[] args) {/* Type your code here. */}}Input code in the "Write code here" sections4: Format.cpp) Write a program that gets two real values from the user, prints their sum and product in scientific notation, and prints their sum and product in fixed point notation. Print answers to three decimal places.
- (a && b) || (c&&d) only gives true when: any of a, b, c, d is true both a,b are true all, a, b, c, d are true a,b is ture or c.d is true O None of aboveLO: (Remember) Students will recall how to read from standard input. LO: (Apply) Students will write loops that iterate as long as a condition is true. Write a program that reads words from standard input and displays them to standard output. When the word "end" is read, print it out and then stop reading input. Full Screen * maln.cpp New #include 2 using namespace std; 1 3 4- /* 5 * Reads and displays words from standard input until hitting a stop word. 6 */ 7- int main() { 8 9. 10 return 0; 11 annWrite EXACTLY what is printed by the code
- Program thisWrite EXACTLY what is printed by the code in 2 iii)(Financial: credit card number validation) Credit card numbers follow certain pat- terns. A credit card number must have between 13 and 16 digits. It must start with: 4 for Visa cards 5 for Master cards 37 for American Express cards 6 for Discover cards In 1954, Hans Luhn of IBM proposed an algorithm for validating credit card numbers. The algorithm is useful to determine whether a card number is entered correctly or whether a credit card is scanned correctly by a scanner. Credit card numbers are generated following this validity check, commonly known as the Luhn check or the Mod 10 check, which can be described as follows (for illustra- tion, consider the card number 4388576018402626): 1. Double every second digit from right to left. If doubling of a digit results in a two-digit number, add up the two digits to get a single-digit number. 4388576018402626 → 2 * 2 = 4 → 2 * 2 = 4 → 4 * 2 = 8 → 1 * 2 = 2 6 * 2 = 12 (1+ 2 = 3) → 5 * 2 = 10 (1+ 0 = 1) → 8 * 2 = 16 (1 + 6 = 7) → 4 * 2 = 8