IR Spectrum (KBr disc) 4000 100 80 60 40 20 40 13C NMR Spectrum (50.0 MHz, CDCI, solution) % of base peak 10 3000 9 59 83 DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 80 11.0 101 exchanges with D₂0 8 2000 120 V (cm'¹) 142 1722 1680 1600 160 Amer 1200 m/e 10.0 ppm 7 M+160 (1%) 160 6 800 Mass Spectrum 120 200 240 280 C7H1204 5 solvent 80 4 3 No significant UV absorption above 220 nm 40 2 08 (ppm) TMS 0 8 (ppm) 1
IR Spectrum (KBr disc) 4000 100 80 60 40 20 40 13C NMR Spectrum (50.0 MHz, CDCI, solution) % of base peak 10 3000 9 59 83 DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 80 11.0 101 exchanges with D₂0 8 2000 120 V (cm'¹) 142 1722 1680 1600 160 Amer 1200 m/e 10.0 ppm 7 M+160 (1%) 160 6 800 Mass Spectrum 120 200 240 280 C7H1204 5 solvent 80 4 3 No significant UV absorption above 220 nm 40 2 08 (ppm) TMS 0 8 (ppm) 1
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Analyze the all this spectrum below and identify the compound
Transcribed Image Text:IR Spectrum
(KBr disc)
4000
100
80
60
40
20
40
13C NMR Spectrum
(50.0 MHz, CDCI, solution)
% of base peak
10
3000
9
59
83
DEPT CH₂ CH₂ CH
proton decoupled
200
¹H NMR Spectrum
(200 MHz, CDCI, solution)
11.0
80
101
exchanges
with D₂O
8
2000
120
V (cm¹)
142
1722 1680
1600
160
Amo
1200
m/e
10.0 ppm
M+160 (1%)
160
800
Mass Spectrum
120
200 240 280
C7H1204
7 6 5
solvent
80
4
No significant UV
absorption above 220 nm
40
3 2
0 8 (ppm)
TMS
8 (ppm)
1
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