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- Ancay youyay eakspay igpay atinlay? (Can you speak pig latin?) If you can’t, here are the rules: If a word begins with a consonant, take all of the letters before the first vowel and move them to the end of the word, then add ay to the end of the word. Examples: pig → igpay, there → erethay. If a word begins with a vowel (a, e, i, o, u, or y), simply add yay to the end of the word. For this problem, y is always a vowel. Examples: and → andyay, ordinary → ordinaryyay. Although there are many variants of Pig Latin (such as Kedelkloppersprook in Germany), for this problem we will always use the rules described above. A friend of yours was frustrated with everyone writing in Pig Latin and has asked you to write a program to translate to Pig Latin for him. Ouldway youyay ebay osay indkay otay oday ityay? (Would you be so kind to do it?) Inputs consist of lines of text that you will individually translate from a text file given by the user. If the file cannot be opened for some reason,…public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string. This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is, str = new StringBuilder(str).reverse().tostring(); A bit convoluted, but does what is needed without fuss or muss. Maybe one day the Java strings will come with the reverse method built in, just like the string data types of all sensible…
- please type so that i may be able to read itQ1) Write a method that checks whether two words are anagrams. Two words are anagrams if they contain the same letters in any order. For example, "silent" and "listen" are anagrams. Write a test program that prompts the user to enter two strings and, if they are anagrams, displays "anagram", otherwise displays "not anagram". Note: The header of the method is as follows: public static boolean isAnagram(String s1, String s2) Sample Input #1: Enter two strings: Silent listen Sample Output #1: The string “Silent” and “listen” are anagrams. Sample Input #1: Enter two strings: teach peach Sample Output #1: The string “teach” and “peach” aren’t anagrams.Х3: inlTol0 Write a function in Java that implements the following logic: Given a number n, return true if n is in the range 1..10, inclusive. Unless "outsideMode" is true, in which case return true if the number is less or equal to 1, or greater or equal to 10. Your Answer: 1 public boolean in1To10(int n, boolean outsideMode) 2 { 3 } H N M
- Specification: Read sentences from the user until * is entered. Show the number of words in each sentence that contain a stretch of non-z characters with exactly 2 vowels. A stretch starts from the start of the word or after a 'z'. A stretch terminates just before another 'z' or at the end of the word. Examples: 1. Matching words: zoo, azozooza, GONZALEZ 2. Non-matching words: ozo, azoooza The sentences contain no punctuation, the words are separated by one or more spaces, and the characters may be upper or lower case. Keep reading sentences until the user enters "*". Sample I/O: Sentence: azoooza azooza zoo azoo Matching words = 3 Sentence: GONZALEZ passes the ball to VAZQUEZ Matching words = 3 Sentence: azozototzeti Matching words = 1 Sentence: * DoneASAP Solution needed / Solution You're given a string of words. You need to find the word "Nemo", and return a string like this: "I found Nemo at [the order of the word you find Nemo]!" If you can't find Nemo, return "I can't find Nemo :(". Examples findNemo ("I am finding Nemo !") → "I found Nemo at 4!" wwwwwwww ➡ "I found Nemo at 1!" findNemo ("Nemo is me") www findNemo ("I Nemo am") wwwwwwwww "I found Nemo at 2!" (Ctrl)ASAP Solution needed / Solution You're given a string of words. You need to find the word "Nemo", and return a string like this: "I found Nemo at [the order of the word you find Nemo]!" If you can't find Nemo, return "I can't find Nemo :(". Examples findNemo ("I am finding Nemo !") → "I found Nemo at 4!" wwwwwwwww findNemo ("Nemo is me") ➡ "I found Nemo at 1!" findNemo ("I Nemo am") ➡ "I found Nemo at 2!" wwwwwwww (Ctrl)
- Implement the following function which accepts a string as parameter and reverses it, without using any function from the string library. void strReverse(char *str)Oct 13 8:38 Auctirst(); function: O a. converts all letters into upper case O b.converts first letter into uppercase Oc. converts first letter into lower case O d. converts all letters into lower case t of