A closed surface with dimensions a = b0.272 m and c =the figure. The electric field throughout theregion is nonuniform and defined by E(a+ Br)î where r is in meters, a = 3 N/C,and 3 = 5 N/(C -m²).0.4896 m is located as inEWhat is the magnitude of the net chargeenclosed by the surface?Answer in units of C.A.toshWhat is the sign of the charge enclosed in thesurface?R1. Cannot be determined2. Negative3. Positive

Answered: J.4896 m is located ctric field…

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J.4896 m is located ctric field throughou m and defined by is in meters, a = 3

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter25: Gauss’s Law

Section: Chapter Questions

Problem 43PQ: The nonuniform charge density of a solid insulating sphere of radius R is given by = cr2 (r R),...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

A closed surface with dimensions a = b
0.272 m and c =
the figure. The electric field throughout the
region is nonuniform and defined by E
(a+ Br)î where r is in meters, a = 3 N/C,
and 3 = 5 N/(C -m²).
0.4896 m is located as in
E
What is the magnitude of the net charge
enclosed by the surface?
Answer in units of C.
A.
to
sh
What is the sign of the charge enclosed in the
surface?
R
1. Cannot be determined
2. Negative
3. Positive

Expert Solution

Step 1

We know the formula of the electric flux is given as

$ϕ = BAcos (θ) At the surface a from origin is given as ϕ_{1} = (3 + 5 a^{2}) (axb) \cos (180) ϕ_{1} = (3 + 5 \times 0 . 272^{2}) (0.272 x 0272) \cos (180) ϕ_{1} = - 0.249 N / {Cm}^{2}$

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