As a COMMENT IN CODE, please DO Test-Cases on how you would test your solution assumptions and hence your code explore a specific way to perform a Breadth First Search (BFS) of a given Graph [Figure 1].
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Very important: As a COMMENT IN CODE, please DO Test-Cases on how you would test your solution assumptions and hence your code
explore a specific way to perform a Breadth First Search (BFS) of a given Graph [Figure 1].
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- Computer Science QuestionConsider the adjacency list (list of neighbors) data structure for representing a graph. struct node{int data; node * next;};class Graph { …………private:node neighborList[30];int last;};Write a method to print the neighbors of a given node n, void Graph::print(int n){??????}Course: Data Structure and Algorithms Language: C++ Question is well explained Question #2Implement a class for Circular Doubly Linked List (with a dummy header node) which stores integers in unsorted order. Your class definitions should look like as shown below: class CDLinkedList;class DNode {friend class CDLinkedList;private int data;private DNode next;private DNode prev;};class CDLinkedList {private:DNode head; // Dummy header nodepublic CDLinkedList(); // Default constructorpublic bool insert (int val); public bool removeSecondLastValue (); public void findMiddleValue(); public void display(); };TranposeGraph import java.io.*; import java.util.*; // This class represents a directed graph using adjacency list // representation class ALGraph{ private int vertices; // No. of vertices // Array of lists for Adjacency List Representation private LinkedList adj[]; // Constructor ALGraph(int vertices) { this.vertices = vertices; adj = new LinkedList[this.vertices]; for (int i=0; i getAdjacentList(int v) { return adj[v]; } //Function to add an edge into the graph void addEdge(int v, int w) { adj[v].add(w); // Add w to v's list. } // TODO Transpose graph // If the graph includes zero vertices, return null // Create a new ALGraph // For every vertex, retrieve its adjacent list, make a pass over the list and rewrite each edge (u, v) to be (v, u) and add the u into the adjacent list of v public ALGraph transpose(){…
- /** * This class will use Nodes to form a linked list. It implements the LIFO * (Last In First Out) methodology to reverse the input string. * **/ public class LLStack { private Node head; // Constructor with no parameters for outer class public LLStack( ) { // to do } // This is an inner class specifically utilized for LLStack class, // thus no setter or getters are needed private class Node { private Object data; private Node next; // Constructor with no parameters for inner class public Node(){ // to do // to do } // Parametrized constructor for inner class public Node (Object newData, Node nextLink) { // to do: Data part of Node is an Object // to do: Link to next node is a type Node } } // Adds a node as the first node element at the start of the list with the specified…7. ASK class DoublyLinkedList<E> {// define ListNode elements specific for this type of list, indicating current, previous and next// consider head as name for previous node, and tail for the next one.private ListNode<E> head;private ListNode<E> current;private ListNode<E> tail; // default constructorpublic DoublyLinkedList(){//*** Task #1: implement a default constructor here, initializing the nodes to null } // method that calculates the length of the listpublic int length(){//*** Task #2: implement the method navigating through the list until you run out of elements } // method that adds a node at the beginning of the listpublic void addANodeToStart(E addData){//*** Task #3: implement this method, taking into consideration that the head will be replaced by a new node. You may want to use a temporary variable } // accessor method that gets data at current nodepublic E getDataAtCurrent(){//*** Task #4: implement this method making sure to take into account…class Dijkstra(): """ A fully connected directed graph with edge weights """ def __init__(self, vertex_count): self.vertex_count = vertex_count self.graph = [[0 for _ in range(vertex_count)] for _ in range(vertex_count)] def min_distance(self, dist, min_dist_set): """ Find the vertex that is closest to the visited set """ min_dist = float("inf") for target in range(self.vertex_count): if min_dist_set[target]: continue if dist[target] < min_dist: min_dist = dist[target] min_index = target return min_index def dijkstra(self, src): """ Given a node, returns the shortest distance to every other node """ dist = [float("inf")] * self.vertex_count dist[src] = 0 min_dist_set = [False] * self.vertex_count for _ in range(self.vertex_count): #minimum distance vertex that is not processed…
- 2- Explain the Adjacency-list graph representation code public class Graph private final int V; private Bag[] adj; public Graph(int V) { this.V = V; adj = (Bag[]) new Bag[V]; for (int v = 0; v (); } public void addEdge(int v, int w) { adj[v].add(w); adj[w].add(v); public Iterable adj(int v) { return adj[v]; } }template <class T> class List; template <class T> class Node{ friend class List<T>; private: T data; Node* link; }; template <class T> class List{ public: List(){first = 0;} void InsertBack(const T& e); void Concatenate(List<T>& b); void Reverse(); class Iterator{ …. }; Iterator Begin(); Iterator End(); private: Node* first; }; I need algorithm , I think it may use iterator to complile. The question shows on below photo.Array_based circular queue: Define the class Queue using one dimensional circular array representation with no implementation; i.e. declare the data members, and the function members only (Enqueue, Dequeue, IsEmpty, GetHead etc.). Implement the Ennqueue method of the above class
- Define the 3 bolded functions for the following DynIntStack (linked list): class DynIntStack {private: struct Node { int value; // Value in the node Node *next; // Pointer to the next node }; Node *top; // Pointer to the stack toppublic: DynIntStack() { head = nullptr; } void push(int); //assume this is already defined void removeTop(); // removes the top element without returning it int topValue(); // returns the top element without removing it bool isEmpty() { return head == nullptr; } bool isFull() { return false; } void pushMany(int values[], int n); //add n values from the array}; Hints: void removeTop() (hint 3 lines of code) int topValue() (hint 1 line of code) void pushMany(int values[], int n) (hint 2 lines of code, use a for loop, call another function)using namespace std; class SinglyLinkedListNode { // INSERT YOUR CODE HERE }; class SinglyLinkedList { public: SinglyLinkedListNode *head; SinglyLinkedListNode *tail; SinglyLinkedList() { this->head = nullptr; this->tail = nullptr; } voidinsert_node(intnode_data) { // INSERT YOUR CODE HERE } }; void free_singly_linked_list(SinglyLinkedListNode* node) { // INSERT YOUR CODE HERE } // Complete the has_cycle function below. /* * For your reference: * * SinglyLinkedListNode { * int data; * SinglyLinkedListNode* next; * }; * */ bool has_cycle(SinglyLinkedListNode* head) { SinglyLinkedListNode* temp = head; bool isCycle = false; while (temp != nullptr) { // INSERT YOUR CODE HERE } } int main() { // INSERT YOUR CODE HERE TO TEST YOUR CODE return0; }#include <iostream> usingnamespace std; class Queue { int size; int* queue; public: Queue(){ size = 0; queue = new int[100]; } void add(int data){ queue[size]= data; size++; } void remove(){ if(size ==0){ cout <<"Queue is empty"<<endl; return; } else{ for(int i =0; i < size -1; i++){ queue[i]= queue[i +1]; } size--; } } void print(){ if(size ==0){ cout <<"Queue is empty"<<endl; return; } for(int i =0; i < size; i++){ cout<<queue[i]<<" <- "; } cout << endl; } //your code goes here }; int main(){ Queue q1; q1.add(42); q1.add(2); q1.add(8); q1.add(1); Queue q2; q2.add(3); q2.add(66); q2.add(128); q2.add(5); Queue q3 = q1+q2; q3.print();…