A 25 kg crate is placed along the inclined plane 60° from the vertical plane. the coefficient of friction between the crate and the surface is μ = 0.25 and μ = 0.22, If the crates moved upward from rest due to the applied force of 250 N along the horizontal, determine the force needed for equilibrium, velocity when the crate moves 2.5 m and the velocity of the crate when its moved by 2 m if a force of 50 N was applied.

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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C. A 25 kg crate is placed along the inclined
plane 60° from the vertical plane. the
coefficient of friction between the crate and
the surface is µ̟ = 0.25 and Hk = 0.22, If the
crates moved upward from rest due to the
applied force of 250 N along the horizontal,
determine the force needed for equilibrium,
velocity when the crate moves 2.5 m and the
velocity of the crate when its moved by 2 m
if a force of 50 N was applied.
%3D
Transcribed Image Text:C. A 25 kg crate is placed along the inclined plane 60° from the vertical plane. the coefficient of friction between the crate and the surface is µ̟ = 0.25 and Hk = 0.22, If the crates moved upward from rest due to the applied force of 250 N along the horizontal, determine the force needed for equilibrium, velocity when the crate moves 2.5 m and the velocity of the crate when its moved by 2 m if a force of 50 N was applied. %3D
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