In Java please6.20 LAB: Hailstone sequence (EO) Given a positive integer num, the following rules will always create a sequence that ends with 1, called the hailstone sequence:If num is even, divide it by 2If num is odd, multiply it by 3 and add 1 (i.e. 3*num +1)Continue until num is 1Write a method, hailstone(), that takes in a positive integer as a parameter and prints the hailstone sequence starting with that integer. Format the output so that ten integers, each separated by a tab character (\t), are printed per line. Assume the input to the program is always positive.The output format can be achieved as follows:System.out.print(num + "\t");Ex: If the program input is:25the output of method hailstone() is:25 76 38 19 58 29 88 44 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1Note: Your program must define the method:public int hailstone(int num)import java.util.Scanner;public class Hailstone {public static void hailstone(int num){int i = 1;while(num>0){if(num%2==0){System.out.print(num + "\t");num = num / 2;}else {System.out.print(num + "\t");num = num * 3 + 1;}if(i==10){i = 1;System.out.print("");}else i++;if(num==1){System.out.println("1");break;}}}public static void main(String[] args) {Scanner scnr = new Scanner(System.in);Hailstone labObject = new Hailstone();int num;num = scnr.nextInt();labObject.hailstone(num); // Call hailstone() to print out the hailstone sequence.}}

If num is even, divide it by 2 If num is odd, multiply it by 3 and add 1 (i.e. 3*num +1) Continue…

EBK JAVA PROGRAMMING

9th Edition

ISBN:9781337671385

Author:FARRELL

Publisher:FARRELL

Chapter8: Arrays

Section: Chapter Questions

Problem 20RQ

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6.20 LAB: Hailstone sequence (EO)

Given a positive integer num, the following rules will always create a sequence that ends with 1, called the hailstone sequence:

If num is even, divide it by 2
If num is odd, multiply it by 3 and add 1 (i.e. 3*num +1)
Continue until num is 1

Write a method, hailstone(), that takes in a positive integer as a parameter and prints the hailstone sequence starting with that integer. Format the output so that ten integers, each separated by a tab character (\t), are printed per line. Assume the input to the program is always positive.

The output format can be achieved as follows:
System.out.print(num + "\t");

Ex: If the program input is:

the output of method hailstone() is:

25 76 38 19 58 29 88 44 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1

Note: Your program must define the method:
public int hailstone(int num)

import java.util.Scanner;

public class Hailstone {

public static void hailstone(int num){
int i = 1;
while(num>0){

if(num%2==0){
System.out.print(num + "\t");
num = num / 2;
}
else {
System.out.print(num + "\t");
num = num * 3 + 1;
}
if(i==10){
i = 1;
System.out.print("");
}
else i++;
if(num==1){
System.out.println("1");
break;
}

}

public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
Hailstone labObject = new Hailstone();
int num;

num = scnr.nextInt();
labObject.hailstone(num); // Call hailstone() to print out the hailstone sequence.
}
}

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