lanes for the blue and brown allele samples? (circle one) Brown sample: 0 1 Blue sample: 0 1 2 more than two. 2 more than two. 1f: If the student is heterozygous, how many bands will the brown allele samples? (circle one) Brown sample: 0 Blue sample: 0 1 1 2 more than two. 2 more than two.
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- Why is the company Qiagen has more refined DNA extraction steps than a normal Strawberry DNA extraction practical? Summary of Qiagen DNA extraction steps Add ATL buffer and grind with sample. Add 20 microliters of enzyme Proteinase K to degrade protein into a 1.5-2ml microcentrifuge tube. Add 200 microlitres AL lysis buffer, and mix by vortexing for 5–10 seconds, which breaks cell membrane allowing DNA to be released. Incubate the sample at 56 degrees for 10 minutes. Mix the cell lysate with 200 microlitres ethanol by pipetting it at the side of the microcentrifuge wall so DNA precipitates. The DNA forms a white layer and the remaining liquid is discarded. Pipet the mixture into DNeasy Mini spin column placed in a 2 ml collection tube. Centrifuge for a minute at 8000 rpm. Place the mini spin column into a 2 ml collection tube, add 500 µl Buffer AW1, and centrifuge for 1 min at 8000 rpm. Then add it to a new 2 ml collection tube (provided), add 500 µl Buffer AW1, and centrifuge for 1…Select all that would be true if I had a nonsense mutation in an exon of a gene: The nonsense mutant allele would be the same size as wildtype by PCR-electrophoresis The nonsense mutant protein would be the same size by Western as the wildtype protein The nonsense mutant allele would be a different size compared to wildtype by PCR- electrophoresis The nonsense mutant protein would be a different size by Western compared to the wildtype proteinSelect all that would be true if I had a missense mutation in an gene: The missense mutant protein would be the same size by Western as the wildtype protein The missense mutant allele would be a different size compared to wildtype by PCR- electrophoresis The missense mutant protein would be a different size by Western compared to the wildtype protein The missense mutant allele would be the same size as wildtype by PCR-electrophoresis
- Following method is used to study long-range chromosome interactions Digestion by restriction endonuclease Northern Blot Chromatin Immunoprecipitation Chromosome conformation capture assaysThe technique of fluorescence in situ hybridization (FISH) is described. This is another method for examining sequence complexity within a genome. In this method, a DNA sequence, such as a particular gene sequence, can be detected within an intact chromosome by using a DNA probe that is complementary to the sequence.For example, let’s consider the β-globin gene, which isfound on human chromosome 11. A probe complementary to theβ-globin gene binds to that gene and shows up as a brightly colored spot on human chromosome 11. In this way, researchers can detectwhere the β-globin gene is located within a set of chromosomes. Becausethe β-globin gene is unique and because human cells are diploid(i.e., have two copies of each chromosome), a FISH experimentshows two bright spots per cell; the probe binds to each copy ofchromosome 11. What would you expect to see if you used thefollowing types of probes?A. A probe complementary to the Alu sequenceB. A probe complementary to a tandem array near…The temperature at which the primers and target DNA hybridize may be changed to influence the stringency of PCR amplification. What effect will changing the hybridization temperature have on the amplification? Let's say you have a certain yeast gene A and want to check whether it has a human equivalent. How might managing the hybridization's rigor benefit you?
- In the genotype presented (genomic plus plasmid genes), which of the following statements Is phenotype? genome: IS P O`z+Y° plasmid: I* Pt otzY+ no production of either B-gal and permease O B-gal and permease induced when lactose is present no B-gal is produced and expression of permease when lactose is present constitutive expression of B-gal and permease constitutive expression of B-gal and no expression of permeaseYou learned in the chapter that an STR locus is a locus where alleles differ in the number of copies of a short, tandemly repeated DNA sequence. PCR is used to determine the number of alleles present, as shown by the size of the DNA fragment amplified. In the Figure below are the results of PCR analysis for STR alleles at a locus where the repeat unit length is 9 bp, and alleles are known that have 5 to 11 copies of the repeat. Given the STR alleles present in the adults, state whether each of the four juveniles could or could not be an off-spring of those two adults. Explain your answers.DNA Profiles as Tools for Identification A PCR-based paternity test is conducted using STRs that consistently produce a unique DNA fragment pattern from a single chromosome. Examining the results of the following Southern blot, which male(s) can be excluded as the father of the child? Which male(s) could be the father of the child?
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