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Large-Signal (DC) Analysis: RTH RC C V BE VTH (+ VCC = 2.5 V, R1 = 13 kOhm, R2 = 12 kOhm, RC = 1 kOhm, RE = 400 Ohm, Q1: IS = 10 fA, VT = 26 mV, Beta = 110 A/A, VÀ = 0 E RE explain this expression VTH – IBRTH – Vbe IERE In terms of collector Kirchhoff's voltage = 0 equation at input circuit: Ic +1 VTh -Rth – VBe Ic RE = 0 Cument VTH – VBE Ic BRTH + (explain the derivation) Ic= IB B | IE= Ict Ib 1 Eq. 2 B+1 -RE Source: B. Razavi, Fundamentals of Microelectronics

Large-Signal (DC) Analysis: RTH RC C V BE VTH (+ VCC = 2.5 V, R1 = 13 kOhm, R2 = 12 kOhm, RC = 1 kOhm, RE = 400 Ohm, Q1: IS = 10 fA, VT = 26 mV, Beta = 110 A/A, VÀ = 0 E RE explain this expression VTH – IBRTH – Vbe IERE In terms of collector Kirchhoff's voltage = 0 equation at input circuit: Ic +1 VTh -Rth – VBe Ic RE = 0 Cument VTH – VBE Ic BRTH + (explain the derivation) Ic= IB B | IE= Ict Ib 1 Eq. 2 B+1 -RE Source: B. Razavi, Fundamentals of Microelectronics

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Explain the derivation behind the encircled part of the image. Thank you.

 

TOPIC: BIPOLAR AMPLIFIERS

Large-Signal (DC) Analysis: RC RTH Β → B C VC + V BE Z Ic VCC = 2.5 V, R1 = 13 kOhm, R2 = 12 kOhm, RC = 1 kOhm, RE = 400 Ohm, Q1: IS = 10 fA, VT = 26 mV, Beta = 110 A/A, VA = 0 VTH E %3D %3D RE explain this expression In terms of collector Kirchhoff's voltage VTh - IBRTH - VBe IERE = 0 equation at input circuit: ß+1 Ic VrH -Rru – Van VTh RTH - VBE Ic Re = 0 B current (tc) (explain the derivation) B | IE= IctIb VTH – VBE Ic -> Eq. 2 B +1 RE 1 BRTH + Ic= IB Source: B. Razavi, Fundamentals of Microelectronics
Transcribed Image Text:Large-Signal (DC) Analysis: RC RTH Β → B C VC + V BE Z Ic VCC = 2.5 V, R1 = 13 kOhm, R2 = 12 kOhm, RC = 1 kOhm, RE = 400 Ohm, Q1: IS = 10 fA, VT = 26 mV, Beta = 110 A/A, VA = 0 VTH E %3D %3D RE explain this expression In terms of collector Kirchhoff's voltage VTh - IBRTH - VBe IERE = 0 equation at input circuit: ß+1 Ic VrH -Rru – Van VTh RTH - VBE Ic Re = 0 B current (tc) (explain the derivation) B | IE= IctIb VTH – VBE Ic -> Eq. 2 B +1 RE 1 BRTH + Ic= IB Source: B. Razavi, Fundamentals of Microelectronics
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