Learning Goal: To apply the principle of moments and the principle of transmissibility. What is MF,, the contribution to the moment about point O made by the x component of the force F at point A? What is Mp., the contribution to the moment about point O made by the y component of the force F at point A? What is the total moment M due to the force F about point O? Assume that moments acting counterclockwise about point O are positive whereas moments acting clockwise are negative. As shown, a rope is attached to al = 19.0ft high shed that is to be relocated. A man pulls on the end of the rope at point A; the rope is attached to the shed at point B. (Figure 1) As the man pulls on the rope, it creates an angle 0 with the horizontal. The end of the rope is ocated at z = 15.0ft from the shed and y = 5.00ft off the ground. The man pulls on the rope with a force of magnitude F = 70.0lb Express your answers numerically in pound-feet to three significant figures separated by commas. > View Available Hint(s)

Learning Goal: To apply the principle of moments and the principle of transmissibility. What is MF,, the contribution to the moment about point O made by the x component of the force F at point A? What is Mp., the contribution to the moment about point O made by the y component of the force F at point A? What is the total moment M due to the force F about point O? Assume that moments acting counterclockwise about point O are positive whereas moments acting clockwise are negative. As shown, a rope is attached to al = 19.0ft high shed that is to be relocated. A man pulls on the end of the rope at point A; the rope is attached to the shed at point B. (Figure 1) As the man pulls on the rope, it creates an angle 0 with the horizontal. The end of the rope is ocated at z = 15.0ft from the shed and y = 5.00ft off the ground. The man pulls on the rope with a force of magnitude F = 70.0lb Express your answers numerically in pound-feet to three significant figures separated by commas. > View Available Hint(s)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The moment of a force about a point O in a 3D coordinate system is solved by computing the cross product of r x F. If r is given as the vector <10, -8, -12> and F is given as <10, -8, 2> what is the moment of F about point O, i.e. the cross product of the vectors r and F?
F1 F2 F3 A b F4 D F5 Consider the following values: - a = 25 m; b 5 m; c = 25 m; d = 5 m; F1 = 4 kN; F2 = 5 kN; F3 = 6 kN; F4 = 7 kN; F5 = 8 kN; a = 30°, 0 = 60° %3D B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 75.8 kN.m b) 32.7 kN.m c) - 14.6 kN.m d) 72.9 kN.m e) 27.1 kN.m - 66.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) - 198.8 kN.m b) 212.7 kN.m c) - 121.6 kN.m d) 98.9 kN.m e) 125.4 kN.m f) -170.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - 96.7 kN.m b) 251.1 kN.m c) - 114.6 kN.m d) 217.9 kN.m 154.1 kN.m f)-177.7 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 198 kN.m b) 127 kN.m c) – 219 kN.m d) 369 kN.m e) 151 kN.m f) - 171 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Setting
F1 F2 a F3 A d. F4 Consider the following values: F5 a = 25 m;b = 5 m; c = 25 m; d = 5 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30°, 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 15.8 kN.m b) 12.7 kN.m c) - 74.6 kN.m d) 52.9 kN.m e) 24.1 kN.m f)- 47.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 8.8 kN.m b) 2.7 kN.m c) 31.6 kN.m d) 8.9 kN.m e) 5.4 kN.m ) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 86.7 kN.m b) 51.1 kN.m c) 14.6 kN.m d) 27.9 kN.m e) 74.1 kN.m ) 35.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 17.8 kN.m b) 82.7 kN.m c) - 21.9 kN.m d) 36.9 kN.m e) - 27.1 kN.m f) 30.1 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Setting ) 321.3 kN.m a) 111.7 kN.m b) 218.1 kN.m c) 254.6 kN.m d) 93.1 kN.m e) 101.1 kN.m bo
The moment of the force F=960-lb about the point O in Cartesian vector form is. 1 ft 4 ft 2ft Select one: O a. Mo = 1600 – 3200A O b. Mo = -200j + 400k Oc. Mo =-200; – 400k O d. Mo= 200; + 400k 1:15 PM
F1 F2 ba C F3 A B d. b F4 Consider the following values: - F5 a = 7 m; b = 3 m; c = 7 m; d = 3 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30° e = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) 90.8 kN.m b) 72.7 kN.m c) 14.6 kN.m d) 55.9 kN.m e) 21.6 kN.m f) 61.3 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 77.8 kN.m b) 25.7 kN.m c) 38.6 kN.m d) 18.9 kN.m e) 37.9 kN.m f) 84.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 35.7 kN.m b) 21.1 kN.m c) 714.6 kN.m d) 69.1 kN.m e) 51.4 kN.m f) 85.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 17.8 kN.m b) 55.7 kN.m c) 44.6 kN.m d) 18.9 kN.m e) 21.5 kN.m f) 30.1 kN.m 5] What is the moment of the force F2 about point E? a) 81.7 kN.m b) 78.1 kN.m c) 64.6 kN.m d) 73.1 kN.m e) 54.6 kN.m f) 61.3 kN.m
F1 F2 a C F3 A F4 D Consider the following values: - F5 a = 16 m; b = 11 m; c = 13 m; d = 8 m; F1 = 3 kN; F2 = 11 kN; F3 = a = 30°, 0 = 60° , B = 30° 2 kN; F4 = 20 kN; F5 = 2 kN; 1] What is the resultant moment of the five forces acting on the rod about point A? a) 88.8 kN.m b) 76.3 kN.m c) 19.6 kN.m d) 55.5 kN.m e) 59.1 kN.m ) 81.3 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 88.8 kN.m b) 120.8 kN.m c) 31.6 kN.m d) 98.9 kN.m e) 41.1 kN.m ) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 125.7 kN.m b) 178.1 kN.m c) 254.6 kN.m d) 439.1 kN.m e) 144.1 kN.m ) 215.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 77.8 kN.m b) 98.3 kN.m c) 100.6 kN.m d) 18.9 kN.m e) 97.1 kN.m ) 60.1 kN.m 5] What is the moment of the force F2 about point E? Activate W a) 122.7 kN.m b) 108.1 kN.m c) 66.6 kN.m d) 83.1 kN.m e) 111.1 kN.m ) 151.3 kN.m Go to Setting
F1 F2 a F3 d F4 E F5 Consider the following values: - a = 7 m; b = 3 m; c = 7 m; d = 3 m; FI = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30°, e = 60° B= 30° 2] What is the resultant moment of the five forces acting on the rod about point B? a) 77.8 kN.m b) 25.7 KN.m c) 38.6 KN.m a) 18.9 KN.m e) 37,9 KN.m H 84.2 KN.m
STATICS OF RIGID BODIES MOMENT OF A FORCE MOMENT OF A FORCE – SCALAR FORMULATIONMOMENT OF A FORCE – VECTOR FORMULATION Use M = r x F to determine the moment of the force about O. Note: Show r in your diagram.
A: Moment arm of the force In the figure, the dashed line extending from the force vector F is called the line of action of F. The force’s moment arm is the perpendicular distance rm from the pivot point P to the line of action. What is rm, the length of the moment arm of the force F about point P? Express your answer in terms of r and θ. Find the moment M about P due to F. Your answer should correctly express both the magnitude and the sign of M. Express your answer in terms of either rm and F or r, θ, and F. B: As shown (Figure 2), resolve the force vector, F, into radial (parallel to r) and tangential (perpendicular to r) components. Find the magnitude of the radial and tangential components, Fr and Ft. Assume that θis between zero and 90 degrees. Express your answers in terms of F and θ Is the following statement true or false? The moment about point…
30 points The magnitude of the force F = 218 N, is applied at point A and its line of action passes through B. 1. The moment about the origin: MO = ( i + j + k) Nm Express your results using three significant figures.
F1 F2 a C F3 A d b F4 E o Consider the following values: - F5 a = 25 m; b = 5 m; c = 25 m; d = 5 m; F1 = 4 kN; F2 = 2 kN; F3 = 5 kN; F4 = 7 kN; F5 = 3 kN; a = 30° , 0= 60° , B 30° 2] What is the resultant moment of the five forces acting on the rod about point B?
F1 F2 a C F3 F4 E Consider the following values: - F5 a = 1 m; b = 3 m; c = 7 m; d = 3 m; FI = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30°, e = 60° B= 30° 4] What is the resultant moment of the five forces acting on the rod about point D? a) 17.8 kN.m b) 55.7 kN.m c) 44.6 kN.m d) 18.9 KN.m e) 21.5 KN.m ) 30.1 KN.m