x,400a40R,Fig. Equivalent Circuit of IMLest's consider three phase, Y connected, 220 volt(line to line), 7.5 kW, 60 Hz, six pole IM has the following parameter values in /phase referredto the statorR = 0.294 N, R= 0.144 fN, X, = 0.503 N, X, = 0.209N, Xm13.25 NDetermine the following for 0.03 slipa) Electromechanical Torque (Tmech), Electromechanical power (Pmech}.b) Maximum electromechanical torque (Tez), Corresponding speed (n mar)) Electromechanical statrting torque (Tiart), Corresponding stator load current (I, start)a. Tmech63.3705 N. m, Purch 7293.87 W, n.rar = 950.539 rpm, Tmaz153.768 N. m, Ia start= 175.257 A, Tstart = 70.2798 N.b. Tmech= 55.4105 N. m, Pech3933.77 W, n, mur = 919.728 rpm, Tmar154.791 N. m, Iz sart125.567 A. Tart72.5229 N.c. Tmech65.4105 N. m, Prch7872.83 W, n, mar825.827 rpm, T- = 154.758 N. m, 1 stare:145.657 A. Trt73.7912 N.d. Tmech = 65.4105 N.m, Prch= 7973.13 W. n, 969.827 rpm, T = 174.564 N. m, art- 150.265 A. Tytart77.6227 N.e. Tmech = 55.2537 N. m, Pmech2353.62W. nmaz = 925.793 rpm. T220.437 N. m. or115.562 A. Ttart57.7327 N.

According to question: The synchronous speed 'Ns' and motor speed 'Nr' is calculated as The value…

Lest's consider three phase, Y connected, 220 volt(line to line), 7.5 kW, 60 Hz, six pole IM has the following parameter values in 1/phase referred to the stator: R=0.294 N, R= 0.144 N, X, = 0.503 N, X, = 0,209 2, Xm = 13.25 N

Lest's consider three phase, Y connected, 220 volt(line to line), 7.5 kW, 60 Hz, six pole IM has the following parameter values in 1/phase referred to the stator: R=0.294 N, R= 0.144 N, X, = 0.503 N, X, = 0,209 2, Xm = 13.25 N

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Single Phase AC Circuit

Alternating Current (AC) is a type of electric power in which the electric current changes, both in magnitude and direction, at regular intervals. This AC Circuits can deliver power in either a Single Phase system or a Three Phase system.

Question

x,
400
a
40
R,
Fig. Equivalent Circuit of IM
Lest's consider three phase, Y connected, 220 volt(line to line), 7.5 kW, 60 Hz, six pole IM has the following parameter values in /phase referred
to the stator
R = 0.294 N, R= 0.144 fN, X, = 0.503 N, X, = 0.209N, Xm
13.25 N
Determine the following for 0.03 slip
a) Electromechanical Torque (Tmech), Electromechanical power (Pmech}.
b) Maximum electromechanical torque (Tez), Corresponding speed (n mar)
) Electromechanical statrting torque (Tiart), Corresponding stator load current (I, start)
a. Tmech
63.3705 N. m, Purch 7293.87 W, n.rar = 950.539 rpm, Tmaz
153.768 N. m, Ia start= 175.257 A, Tstart = 70.2798 N.
b. Tmech= 55.4105 N. m, Pech
3933.77 W, n, mur = 919.728 rpm, Tmar
154.791 N. m, Iz sart
125.567 A. Tart
72.5229 N.
c. Tmech
65.4105 N. m, Prch
7872.83 W, n, mar
825.827 rpm, T- = 154.758 N. m, 1 stare:
145.657 A. Trt
73.7912 N.
d. Tmech = 65.4105 N.m, Prch= 7973.13 W. n, 969.827 rpm, T = 174.564 N. m, art- 150.265 A. Tytart
77.6227 N.
e. Tmech = 55.2537 N. m, Pmech2353.62W. nmaz = 925.793 rpm. T
220.437 N. m. or
115.562 A. Ttart
57.7327 N.

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