Let a and b be integers, and assume that a or b is even. Without loss of generality, let a be even. (The case where b is even would present the same argument.) Since a is even, there exists an integer k such that a = 2k. ab = (2k) b = 2 (kb) Therefore, ab is even.
Let a and b be integers, and assume that a or b is even. Without loss of generality, let a be even. (The case where b is even would present the same argument.) Since a is even, there exists an integer k such that a = 2k. ab = (2k) b = 2 (kb) Therefore, ab is even.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.2: Exponents And Radicals
Problem 87E
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