Let C be the curve y = 4 ln (16 - x²), for -0.6 ≤ x ≤ 2.9. A graph of y follows. I 10.8 10.5 10.2 9.9 9.6 9.3 9 8.7 8.4 -0.58.1 0.5 1 1.5 2.9 Find the arc length of C = First find and simplify 1 + y2 Now integrate to find arc length = 2.5 1+ y² dx. 2.9 √1+ y² dx =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 81E
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Let C be the curve y = 4 ln(16 – x²), for −0.6 ≤ x ≤ 2.9. A graph of y follows.
H.1
10.8
10.5
10.2
9.9
9.6
9.3
9
8.7
8.4
-8.1
-0.5
0.5
1
1.5
2.9
- Lov
-0.6
First find and simplify √1+ y2
Find the arc length of C =
2 2,5
√1+ y² dx.
-
=
Now integrate to find arc length :
2.9
1.
-0.6
√1+ y² dx =
Transcribed Image Text:Let C be the curve y = 4 ln(16 – x²), for −0.6 ≤ x ≤ 2.9. A graph of y follows. H.1 10.8 10.5 10.2 9.9 9.6 9.3 9 8.7 8.4 -8.1 -0.5 0.5 1 1.5 2.9 - Lov -0.6 First find and simplify √1+ y2 Find the arc length of C = 2 2,5 √1+ y² dx. - = Now integrate to find arc length : 2.9 1. -0.6 √1+ y² dx =
Expert Solution
Step 1

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.

the given function is 

y=4\ln \left(16-x^2\right)

and the given interval is 

[-0.6,2.9]

so the lower and upper limits are

a=-0.6, b=2.9

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