so im having an issue writing this code. the question, plus the errors are shared in screenshots. please, please, if an expert can help me correct this, id immensely appreciate itdef list_gen(d, l): result = [] for k in d: x = [] sorted_dict = dict() sorted_list = list((i, k[i]) for i in l) for i in sorted_list: sorted_dict.setdefault(i[0], i[1]) for key, value in sorted_dict.items(): if key in l: x.append(value) result.append(x) return result ERROR when running test_list_gen_empty: Python crashed running list_gen because:local variable 'sorted_list' referenced before assignmentPASSEDtest_list_gen_extra_keys:I called list_gen ([{"case_number": "22-1660390", "incident_datetime": "2022-06-15T10:51:48.expecting the result to be [["10"]],and it was!FAILED test_list_gen_extra_keys:I called list_gen ([{"case_number": "22-1650418", "incident_datetime": "2022-06-14T11:45:48.expecting the result to be [["2022-06-14T11:45:48.000", "Tuesday"], ["2022-06-19T14:06:00.0but your function returned [["2022-06-15T10:51:48.000", "Wednesday"], ["2022-06-15T10:51:48FAILED test_list_gen_multi_entries:I called list_gen ([{"hour_of_day": "23"}, {"hour_of_day": "8"}], ["hour_of_day"])expecting the result to be [["23"], ["8"]],but your function returned [["8"]].FAILED test_list_gen_random_key_order:I called list_gen([{"incident_datetime": "2022-08-03T13:30:00.000", "day_of_week": "Wednesdexpecting the result to be [["2022-08-03T13:30:00.000", "Buffalo Police are investigating tbut your function returned [["2022-08-03T13:30:00.000", "Buffalo Police are investigating tPASSED test_list_gen_single_entry:I called list_gen([{"incident_description": "Buffalo Police are investigating this report oexpecting the result to be [["Buffalo Police are investigating this report of a crime. Itand it was!FAILED test_list_gen_single_entry:I called list gen([{"day of week": "Friday", "incident datetime": "2022-04-22T01:31:35.000" list_genDefine a function named is open with Google Paraineters. The first parameter will be a list ofdictionaries. The second parameter will be a list of strings (dictionary keys)..The function needs to return a list of lists. The length of the returned list must be identical to thelength of the first parameter. The order of these dictionaries will be paralleled in the entries inthe returned list. (So the first entry will be the list created for the first dictionary; the second entrywill be the list created for the second dictionary, and so on.)Each entry in the returned list will contain a list of values from that dictionary. The secondparameter's entries specify the keys whose values should be added to this list. The order ofthese values must parallel the order of the keys in the second parameter. (So first will be thevalue associated with the second parameter's first entry, second will be the value associatedwith the second parameter's second entry, and so on.) You SHOULD assume that everydictionary will contain all of the keys from the first parameter.Python creates a new list only when a variable is assigned a list literal. You MUSTinclude the statement initializing the variable to which the dictionary's values are addedINSIDE the for-loop iterating through the first parameter.As an example, if this were a function call:list_gen ([{'Used Key': 'Data', 'Unused Keys' : 'More Data' }],['Used Key'])the expected return value would be:[ ['Data']]As an second example, if this were a function call:list_gen ([{'Hint': 'Length 2 Not Required', 'Num' : 8675309),{'Num': 1, 'Hint': 'Use 1st param order'}],['Hint', 'Num'])the expected return value would be:[ ['Length 2 Not Required', 8675309],['Use 1st param order', 1] ]Page 3 / 4+

Question

so im having an issue writing this code.   the question, plus the errors are shared in screenshots.   please, please, if an expert can help me correct this, id immensely appreciate itdef list_gen(d, l):  result = []  for k in d:    x = []    sorted_dict = dict()    sorted_list = list((i, k[i]) for i in l)  for i in sorted_list:    sorted_dict.setdefault(i[0], i[1])  for key, value in sorted_dict.items():    if key in l:      x.append(value)      result.append(x)  return result ERROR when running test_list_gen_empty: Python crashed running list_gen because:local variable 'sorted_list' referenced before assignmentPASSEDtest_list_gen_extra_keys:I called list_gen ([{&#34;case_number&#34;: &#34;22-1660390&#34;, &#34;incident_datetime&#34;: &#34;2022-06-15T10:51:48.expecting the result to be [[&#34;10&#34;]],and it was!FAILED test_list_gen_extra_keys:I called list_gen ([{&#34;case_number&#34;: &#34;22-1650418&#34;, &#34;incident_datetime&#34;: &#34;2022-06-14T11:45:48.expecting the result to be [[&#34;2022-06-14T11:45:48.000&#34;, &#34;Tuesday&#34;], [&#34;2022-06-19T14:06:00.0but your function returned [[&#34;2022-06-15T10:51:48.000&#34;, &#34;Wednesday&#34;], [&#34;2022-06-15T10:51:48FAILED test_list_gen_multi_entries:I called list_gen ([{&#34;hour_of_day&#34;: &#34;23&#34;}, {&#34;hour_of_day&#34;: &#34;8&#34;}], [&#34;hour_of_day&#34;])expecting the result to be [[&#34;23&#34;], [&#34;8&#34;]],but your function returned [[&#34;8&#34;]].FAILED test_list_gen_random_key_order:I called list_gen([{&#34;incident_datetime&#34;: &#34;2022-08-03T13:30:00.000&#34;, &#34;day_of_week&#34;: &#34;Wednesdexpecting the result to be [[&#34;2022-08-03T13:30:00.000&#34;, &#34;Buffalo Police are investigating tbut your function returned [[&#34;2022-08-03T13:30:00.000&#34;, &#34;Buffalo Police are investigating tPASSED test_list_gen_single_entry:I called list_gen([{&#34;incident_description&#34;: &#34;Buffalo Police are investigating this report oexpecting the result to be [[&#34;Buffalo Police are investigating this report of a crime. Itand it was!FAILED test_list_gen_single_entry:I called list gen([{&#34;day of week&#34;: &#34;Friday&#34;, &#34;incident datetime&#34;: &#34;2022-04-22T01:31:35.000&#34; list_genDefine a function named is open with Google Paraineters. The first parameter will be a list ofdictionaries. The second parameter will be a list of strings (dictionary keys)..The function needs to return a list of lists. The length of the returned list must be identical to thelength of the first parameter. The order of these dictionaries will be paralleled in the entries inthe returned list. (So the first entry will be the list created for the first dictionary; the second entrywill be the list created for the second dictionary, and so on.)Each entry in the returned list will contain a list of values from that dictionary. The secondparameter's entries specify the keys whose values should be added to this list. The order ofthese values must parallel the order of the keys in the second parameter. (So first will be thevalue associated with the second parameter's first entry, second will be the value associatedwith the second parameter's second entry, and so on.) You SHOULD assume that everydictionary will contain all of the keys from the first parameter.Python creates a new list only when a variable is assigned a list literal. You MUSTinclude the statement initializing the variable to which the dictionary's values are addedINSIDE the for-loop iterating through the first parameter.As an example, if this were a function call:list_gen ([{'Used Key': 'Data', 'Unused Keys' : 'More Data' }],['Used Key'])the expected return value would be:[ ['Data']]As an second example, if this were a function call:list_gen ([{'Hint': 'Length 2 Not Required', 'Num' : 8675309),{'Num': 1, 'Hint': 'Use 1st param order'}],['Hint', 'Num'])the expected return value would be:[ ['Length 2 Not Required', 8675309],['Use 1st param order', 1] ]Page 3 / 4+

Accepted Answer

Algorithms:

START
Make an empty list to hold the results.
loop through each dictionary
-- Make an…