Answered: magnification

Science

Physics

magnification

University Physics Volume 3

17th Edition

ISBN:9781938168185

Author:William Moebs, Jeff Sanny

Publisher:William Moebs, Jeff Sanny

Chapter2: Geometric Optics And Image Formation

Section: Chapter Questions

Problem 37P: An object 1.50 cm high is held 3.00 cm from a person’s cornea, and its reflected image is measured...

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Concept explainers

Applications Of Reflection Of Light

When a light ray (termed as the incident ray) hits a surface and bounces back (forms a reflected ray), the process of reflection of light has taken place.

Sign Convention for Mirrors

A mirror is made of glass that is coated with a metal amalgam on one side due to which the light ray incident on the surface undergoes reflection and not refraction.

Question

What would be the magnification on an object if the height of the image is 10 cm and the height of the object is 50 cm? Describe the condition of the image, i.e. upright or inverted, enlarged or diminished. Show all work for full credit.

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An object 1.50 cm high is held 3.00 cm from a person’s cornea, and its reflected image is measured to be 0.167 cm high. (a) What is the magnification? (b) Where is the image? (c) Find the radius of curvature of the convex mirror formed by the cornea. (Note that this technique is used by optometrists to measure the curvature of the cornea for contact lens fitting. The instrument used is called a keratometer, or curve measurer.)
A converging lens has a focal length of 20.0 cm. Locate the image for object distances of (a) 40.0 cm, (b) 20.0 cm, and (c) 10.0 cm. For each case, state whether the image is real or virtual and upright or inverted. Find the magnification in each case.
The radius of the curvature for a converging mirror is 36 cm. What is its focal length, in cm? Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.
An object is 12.0 cm from a converging lens (focal length = 15.0 cm). Determine the image magnification. Enter the numerical part of your answer to two significant figures. Hint: Remember that the sign of the magnification is significant.
What is the power of a 27.7-cm-focal-length lens? Express your answer using three significant figures. ? P = = D Is this lens converging or diverging? converging O diverging
A spider is 2.00 m from a wall. You wish to place a lens somewhere in between the spider and the wall, such that the lens forms a real image of the spider at the exact location of the wall, with a magnification of -1/2. a) How far must the lens be placed from the wall? Show your work. b) What must be the focal length of the lens? Show your work.
Find the image distance and image height of the image formed on the following cases. Then, describe whether the image formed is on the same or opposite side of the object, upright or inverted image, and smaller or bigger than the object. 4) A 19-cm high object is placed 71 cm from a converging lens. The focal length is 35 cm. 5) A 26.50-cm high object is placed 40 cm from a diverging lens. The focal length is 20 cm.
If an object is 12 cm away from a converging lens of focal length 4 cm where will the image be? Calculate magnification. Draw a ray diagram of how this image is formed ?
A. If a 4.3 cm doll is standing away from a converging lens and the focal length is 8.2 m, find the image distance, magnification, and image height from 4, 8, and 10 m away. B. Determine if the image is real or virtual, inverted or erect, and smaller or larger. Use the formula below:
Use the worked example above to help you solve this problem. An object 2.88 cm high is placed 19.2 cm from a convex mirror with a focal length of 7.70 cm. (a) Find the position of the image. cm(b) Find the magnification of the mirror.(c) Find the height of the image. cm
An erect object is 15 cm from a concave mirror of radius 9 cm. What is the lateral magnification of the image? Express your answer with at least two decimal places. Note: When entering your final answer in the input box, include the sign if the answer involves a negative sign e.g. -14.22. If positive, there's no need to include the sign.
Two thin lenses with focal lengths of magnitude 15.0 cm, the first diverging and the second converging, are placed 12.00 cm apart. An object 3.00 mm tall is placed 5.50 cm to the left of the first (diverging) lens. Where is the image formed by the first lens located? Please provide a detailed explanation of the process. How far from the object is the final image formed? Please describe the steps taken to reach to your conclusion.