maximum value for the load R.
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- An aluminium channel section is shown in the figure below: mm 1; mm mm li mm As indicated, the horizontal sides are of length / = 167 mm and thickness 1 - 1 mm while the vertical side is of length l2- 218 mm and thickness 12 - 3 mm. Determine the shear stress in the top side when it is subject to a pure torque of 20 Nm. You may assume that the factor ki may be taken as 0.333. Give your answer in N/mm² to three decimal places.Part 2 * Your answer is incorrect. The z-component of momemt M will cause compression at A and B, and tension at C and D. The y-component of moment M will cause compression at A and D, and tension at B and C. The maximum tensile bending stress will occur at point C. Calculate the magnitude of the largest bending moment that can be applied so that the stress at corner C does not exceed 205 MPa. Answer: M- eTextbook and Media Save for Later Part 3 8.31E1 Answer: M-i The z-component of moment M will cause compression at A and B, and tension at C and D. The y-component of moment M will cause compression at A and D, and tension at B and C. The maximum compressive bending stress will occur at point A. Calculate the magnitude of the largest bending moment that can be applied so that the stress at corner A does not exceed 205 MPa. eTextbook and Media Save for Later Part 4 kN-m * Your answer is incorrect. kN-m Submit Answer Determine the maximum bending moment that can be applied to this cross…A small aluminum alloy [E = 73 GPa] teeshape is used as a simply supported beam as shown. For this beam, a = 150 mm. The cross- sectional dimensions of the teeshape are b = 25 mm, d= 38 mm, and t=7 mm. After loads are applied to the beam at B, C, and D, a compressive normal strain of 490cis measured from a strain gage located at c= 9 rmm below the topmost edge of the tee stem at section 1-1. What is the applied load P? 3P Strain gage d a a H Answer: P = i
- An aluminum rod is rigidly attached between a steel rod and a bronze as shown. Axial loads are applied at the positions indicated. Find the stress of each rod in MPa. Steel Aluminum Bronze A- 500mm A = 400mm? A- 200mm 40KN 10KN 20KN 1.5m 2.5m 2.0m Determine the change in length of steel rod having a length of 800mm and a diameter of 6.5mm. The rod is subjected to a force P equal to 110KN. Young's Modulus is 200GPA Compute normal strain of the rodSIMPLE STRESSES 340 mm 3. Two plates are connected by bolts as shown in the figure. Compute the maximum force F that can be applied to the plates. The allowable axial stress of each plate is 150 Mpa. The allowable shear stress of each bolt is 50 MPa. The diameter of each bolt is 16 F F 150 mm 啡 F mm. 50 mm 340 mmThe light rigid bar ABCD shown in the × figure is pinned at B and connected to two vertical rods. Assuming that the bar was initially horizontal and the rods stress-free and load P = 20 kips is applied. 4 ft Aluminum L = 4ft A = 0.75 in² E = 10 x 106 psi Steel L = 3ft A = 0.5 in² E = 29 x 106 psi k2A2A A. What is the stress experienced by aluminum rod B. What is the stress experienced by steel rod. C. What is the resulting deformation on the aluminum rod.
- A load P is applied to a steel component which is supported an aluminum plate into which a 12 mm diameter hole has been drilled. Knowing that the maximum allowable shearing stress is 86.5 MPa in the steel and 160 MPa in the aluminum plate, determine the largest load which may be applied to the steel component. Provide your answer in kN with precision to two decimal points. 10 mm Answer: 12 mm 40 mm P 8 mmThe shown plate is 60 mm thick and it is made of Magnesium Am1004-T61. The plate is fitted between the rigid frictionless supports as shown and at T, = 20°C it is stress free. Find the stresses in the x and y directions when the temperature increases to T, = 58°C. %3D 150 mm 150 mm Select one: O x: 0 MPa, y: 42.864 MPa Ox: 22.1 MPa, y: 44.2 MPa Ox: 0 MPa, y: 44.2 MPa Ox: 0 MPa, y: 17.8 MPa O x: 13.2 MPa, y: 44.2 MPa Ox: 0 MPa, y: 67.4 MPa 3:10 PM O G 4) ENG 1/31/2021Situation 2 For the assembly shown, determine the stress in each of the two vertical rods if the temperature rises 40°C after the load P=50 KN is applied. Neglect the deformation and the mass of the horizontal bar AB. Compute the vertical movement under the load. Steel Aluminum E=200 GPa E=70 GPa L-4m A=300 mm? a-11.7x10*/°C L-3m A=900 mm a=23x10“ /°C 3 m 3 m 3 m Situation 3
- Question: A 12 mm thick plate is connected to two 8 mm thick plates, on either side through a 16 mm diameter power driven field rivet as shown in the figure below. Assuming permissible shear stress as 9- MPa and permissible bearing stress as 270 MPa in the rivet, the rivet value of the joint is P/2 - F 8 mm 8 mm ↓ 12 mm PQ # 4: An aluminum rod is rigidly attached between a steel rod and a bronze rod as shown in Figure. Axial loads are applied at the positions indicated. The value of P is limited to 20 KN in bronze, 72 KN in aluminum and 28 KN in steel Find the area of each section that will not exceed a stress in steel of 280 MPa, in aluminum of 180 MPa, or in bronze of 200 MPa. CLO -2 Steel Aluminum Bronze 2P 4P 2.5 2.0 1.5Two plate are joint by five rivets of 20 mm diameter. What is the shear stress in the material if the shear forces is 18840 N O 12 N/mm2 O 20 N/mm2 O 15 N/mm2