The arms of a Hartnellgovernor are of equal length.When the sleeve is in the mid-position, the masses rotate ina circle with a diameter of 150 mm (the armsare vertical in the mid-position). Neglectingfriction, the equilibrium speed for this positionis 360 rpm. Maximum variation of speed, takingfriction into account, is to be 6% of the mid-position speed for a maximum sleeve movementof 30 mm. The sleeve mass is 5 kg and the frictionat the sleeve is 35 N.Assuming that the power of the governor issufficient to overcome the friction by 1% changeof speed on each side of the mid-position, find(neglecting obliquity effect of arms), the(i) mass of each rotating ball(ii) spring stiffness(iii) initial compression of the spring

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Answered: The arms of a Hartnell governor are of…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Ruler of the "Porter" model, with the upper and lower arms of 178 mm each, fixed by a hinge 38 mm away from the center of rotation. The rotating balls have a mass of 1.15 kg each, and the axial weight affecting the bushing is 20 kg. The ruling commotion began =154. Elevation at 280rpm - The joints are at an angle of 30 to the vertical. Assuming that the force of friction is constant, find the minimum and maximum rotational speed when mg The angle of inclination of the arms to the vertical is 45
Figure shown represents a schematic diagram of a Porter governor. Each fly ball weighs 16.1 lb and the central weight D is 40 lb. Determine the rotational speed in rpm about the vertical axis AD at which the weight D begins to rise. Answer: n=109 rpm
Q2/ The six cylinder of a single- acting, two-stroke cycle Diesel engine are pitched 1 m apart 300 mm and the ratio of and the cranks are spaced at 60° intervals. The crank length connecting rod to crank is 4.5. The reciprocating mass per line is 1.35 Mg. The speed is 200 rev/min. Show with regard to primary and secondary balance, that the firing order 1-5-3-6-2-4 gives unbalance in primary moment only, and the order 1-4-5-2-3-6 gives secondary moment unbalance only. Compare the maximum values of these moments, evaluating with respect to the central plane of the engine.
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The agricultural machine is powered by an electric motor through a flat beltsystem. The machine requires 6 flat belts and 40 kW power to operate at aspeed of 350 rpm. The pulley diameter of the machine is 650 mm and the pulleyof the electric motor is 330 mm. The centre distance between the pulleys is1100 mm. The belt speed is not to exceed 30 m/s. Calculate the tensions in thebelt.
Determine the following : (a) Tension in each cable when at the bottom (b) the minimum angular velocity in rpm to sustain themotion (refer to the image below)
In a four bar mechanism the link AB rotates with angular velocity of 20rad/s and angular acceleration of 100 rad/s both in clockwise direction when it make an angle of 45° with link AD which is fixed .The length of various linkages are AB=CD=400 mm,BC=500mm and AD=750mm .Neglect the gravitational effect and friction.The mass of link is 5kg/m. Find the torque on output link E (2) (4) A (1) (1)
A flywheel weights 592 kg with a diameter 1.4 m. The flywheel rotates at 979 revolution per minute (rpm). If a constant braking torque 522 N.m is applied to the shaft during the rotation, calculate the number of revolutions turned through before the flywheel is coming to a complete stop.
Q/A circular disc of mass m and radius r is Qil 'connected to two springs. If it is free to roll onarough horizoutal surface without_slipping, use energy methad to calculat the System natural Trequency.
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B r P F A UBC Engineering Your team is prototyping a simple braking system for your model car. The 3.4 kg wheel with a radius of r = rad 0.15 m is rotating at w = 18 - .A servo motor can apply a variable force F, which in its first two seconds of operation is equal to F = 10t N and afterwards is equivalent to a constant force of F = 20 N . If the coefficient of kinetic friction between the braking arm and the wheel is μ= 0.2, determine the time needed for the wheel to come to a full stop. The point of contact P between the wheel and the arm is a distance r = -0.2 + 0.26 ĵ m from point A. The force of the servo motor is applied at exactly half of the horizontal distance to A from the point of contact. Assume the wheel can be treated as a disk and that the braking arm is massless. t =
ower shaft running at a steady speed of 175 rev/min driy 8 single-plate friction clutch of external and intern mm respectively. The masses on the countershaft have £ 250 mm and a total mass of 350 kg. The axial spring I 198 450 N, and 4 = 0-3. Assuming uniform acceleration guired to reach full speed from rest, and the work dissipad during that time. (U. Lond.) (Ans. : 99 g

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