mole sample of liquid ammonia at 273 Kelvin is cooled to liquid ammonia at 240 Kelvin. The process is done irreversibly by placing the sample in liquid nitrogen at 77 Kelvin. The heat capacity relationship for ammonia gas is given below. Assuming that the heat of vaporization is 23.4 KiloJoules per mole, answer the questions that follow. What is the entropy change of this process (in Joules per Kelvin)? Express answer in THREE SIGNIFICANT FIGURES. What is the entropy change of the surroundings for this process (in Joules per Kelvin)? Express answer in THREE SIGNIFICANT FIGURES. What is the total entropy change (or the entropy of the universe) for this process (in Joules per Kelvin)? Express answer in THREE SIGNIFICANT FIGURES.

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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A mole sample of liquid ammonia at 273 Kelvin is cooled to liquid ammonia at 240 Kelvin. The process is done irreversibly by placing the sample in liquid nitrogen at 77 Kelvin. The heat capacity relationship for ammonia gas is given below. Assuming that the heat of vaporization is 23.4 KiloJoules per mole, answer the questions that follow.

  • What is the entropy change of this process (in Joules per Kelvin)? Express answer in THREE SIGNIFICANT FIGURES.
  • What is the entropy change of the surroundings for this process (in Joules per Kelvin)? Express answer in THREE SIGNIFICANT FIGURES.
  • What is the total entropy change (or the entropy of the universe) for this process (in Joules per Kelvin)? Express answer in THREE SIGNIFICANT FIGURES.
С, 3 24.6 + 3.75 х10-2 T — 1.38 х10-6 T2
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Transcribed Image Text:С, 3 24.6 + 3.75 х10-2 T — 1.38 х10-6 T2 %3D
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