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- You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty. Function Description Complete the insertNodeAtTail function in the editor below. insertNodeAtTail has the following parameters: SinglyLinkedListNode pointer head: a reference to the head of a list int data: the data value for the node to insert Returns SinglyLinkedListNode pointer: reference to the head of the modified linked list Input Format The first line contains an integer , the number of elements in the linked list.The next lines contain an integer each, the value that needs to be inserted at tail. Constraints Sample Input STDIN Function ----- -------- 5 size of linked list n = 5 141 linked list data values…Notice that all of the data in the inner lists are represented as strings. You are to write the function convert_data, which should make modifications to the inner lists according to the following rules: If and only if a string represents a whole number (ex: '3' or '3.0'), convert the string to an int. If and only if a string represents a number that is not a whole number (ex: '3.14'), convert the string to a float. Otherwise, leave the string as a str.HINT: The provided helper function is_number may be used (attached image). QUESTION: Complete the docstring below.def convert_data(data: List[list]) -> None: """Convert each string in data to an int if and only if it represents a whole number, and a float if and only if it represents a number that is not a whole number. >>> d = [['abc', '123', '45.6', 'car', 'Bike']] >>> convert_data(d) >>> d [['abc', 123, 45.6, 'car', 'Bike']] >>> d = [['ab2'], ['-123'], ['BIKES', '3.2'],…4. Modify the bracketsBalance function so that the caller can supply the brackets to match as arguments to this function. The second argument should be a list of beginning brackets, and the third argument should be a list of ending brackets. The pairs of brackets at each position in the two lists should match; that is, position 0 in the two lists might have [ and], respectively. You should be able to modify the code for the function so that it does not reference literal bracket symbols, but just uses the list arguments. (Hint: The method index returns the position of an item in a list.) the bracketsBalance function: def bracketsBalance(exp):"""exp is a string that represents the expression""" stk = LinkedStack() for ch in exp: if ch in [’[’, ’(’]: stk.push(ch) elif ch in [’]’, ’)’]: if stk.isEmpty(): # Create a new stack # Scan across the expression # Push an opening bracket # Process a closing bracket# Not balanced return FalsechFromStack = stk.pop()# Brackets must be of…
- Scenario Imagine that you have some data in a list that contains a lot of duplicates that you want to remove, but for simplicity’s sake, you want to avoid writing a for loop and building a new list. Aim The aim of this activity is to build a set out of a random set of items. Write a function called list_to_set that takes a list and turns it into a set. Do not use a for loop or while loop to do so.def fun_a(cards): """ cards is a list of int numbers ranging between 0 to 12 inclusive. We use the number to represent the card's rank in a deck of card. 0 is '2', 1 is '3', ...,9 is 'J', 10 is 'Q', 11 is 'K' and 12 is 'A' This function is to check if there is four of a kind in the cards (4 cards of the same rank) and a fifth card as a kicker to form a four of a kind hands with 5 cards total. The 5 cards look like this: x x x x y (x might be the same as y). If there is more than one way to form such a hand with given cards, choose x that has the highest ranking (that has 4 cards of rank x), and choose y that has the highest ranking in the remaining cards after removing 4 x's. return (x, y) if such a hand exists. otherwise return None. """this code should be in python: write a function that receives a list as its only parameter. Inside the function remove all the duplicate items from the list and returns a new list. For Example: If we call the function with [“dad”, “aunt”, “mom”, “sister”, “mom”] as its input, the returned value should be [“dad”, “aunt”, “mom”, “sister”]. The order of the items inside the returned list does not matter.
- Write a function with below starting function: public static void printFirstAnd Last(ArrayList list) The approach should accomplish the following: Print "no elements" if the list is empty. Print the single element in the list if there is only one. Print the first entry in a list with more than one element, followed by a space, and then the last element.define two lists of numbers (arrays) and ask the user to give the size of each, and then ask the user to fill the list(according to a size that he gave), then compare two arrays and determine whether they are equal? (Note: two arrays are equal if all elements are equal.)from surround import surround inputs = [] [] answers = L = ["tank", "godzilla", "tank"] ["tank"] inputs.append (L) answers.append(a) a = TESTS len(inputs) passed = 0 for i in range(TESTS): try: result = surround (inputs[i]) if result not in answers[i]: print("Error found for input: " + str(inputs[i])) else: passed += 1 except Exception: pass result = "Tests passed: + str(passed) + "/" + str(TESTS) print(result)
- You can shuffle a list using random.shuffle(lst). Write your own function without using random.shuffle(lst) to shuffle a list and return the list. Use the following function header:def shuffle(lst):Write a test program that prompts the user to enter a list of numbers, invokes the function to shuffle the numbers, and displays the numbers.In python, create a function wherein you transfer elements from a list into different lists. If a certain element has been encountered, continue the listing in a new list. Continue doing so until this certain element has been encountered two times. Disregard the succeeding elements after the second certain element. Once you have your 2 lists, return them both as a tuple. Example: element_stop = ‘a’ original_list = [‘b’, ‘c’, ‘d’, ‘d’, ‘f’, ‘a’, ‘e’, ‘t’, ‘d’, ‘g’, ‘f’, ‘t’, ‘a’, ‘b’, ‘e’] The output should be: ([‘b’, ‘c’, ‘d’, ‘d’, ‘f’], [‘e’, ‘t’, ‘d’, ‘g’, ‘f’, ‘t’])Write a program with two functions: addToList(food): printList(food): Print the entire list food is used to pass a list to the function. Ask the user to input another food item. The main program will create a list: myList["apple", "oralge", "grapes] Call the function printList, using myList Call the function addToList, using myList Call the function printList, using myList