ndividual 1-2 is genotype GG + Gg + gg ndividual II-2 is genotype GG + Gg + gg ndividual II-6 is genotype GG + Gg + gg Individual II-1 is genotype GG + Gg + gg GG + Gg + g9 Individual III-2 is genotype GG + Gg gg Individual IV-3 is genotype
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- TTGG ttgg F1 TG tg F2 TtGg Which types of genotypes are represented in F1 and F2 in the above figure, respectively? heterozygous and heterozygous heterozygous and homozygous homozygous and heterozygous homozygous and homozygousFOIL each parent’s genotypes: tall green pea plant (TTGg) TG_ Tg TG Tg short white pea plant (TtGg) TG Tg_ tG_ tg TTGG | TTGG TTgg TTGG TtGg TTGG TtGg Ttgg TEGG TtGg ttGG ttGg TtGg Ttgg ttGg ttgg How many of the 16 offspring are: tall & green 9. tall & white 3 short & green 3 short & white 1 2.) A tall green pea plant (TtGg) is crossed with a Short yellow pea plant (ttgg). FOIL each parent's genotypes: tall green pea plant (TtGg) short white pea plant (ttgg) XW O () ENG 9:37 am O GENBIO-1ST-SEM-MIDTERN X 9 Schoology G karyotype of a certain huma x 6 BigBlueButton - GNBIO Messenger My Questions | bartleby + A app.schoology.com/common-assessment-delivery/start/5385424680?action=Donresume&submissionld=643190401 The diagram below shows a karyotype of a certain human. 8. 10 11 12 13 14 15 16 17 18 19 21 22 X Y Based on the karyotype, which of the following statements is most likely true? O The individual has a genetic condition caused by a nondisjunction event. The individual has a genetic condition caused by the X and Y chromosomes being different sizes. O The individual has a genetic condition caused by a chromosomal duplication. O The individual has a genetic condition caused chromosomes number one being different sizes. GENBIO-1ST-SEM-.pdf O 245180335_56899...jpg Show all ... TID N DAD × IDD . I ID.
- - 1 attachment If these two individuals with the following genotypes are crossed Parent 1: AAbbCCDDeeFf Parent 2: aaBBccddEEFf What is the expected genotypic ratio of the F, generation? (3 pts) A. ¼ AaBbCcDdEeFf: ½ AaBbCcDdEeFF: ¼ AaBbCcDdEeff B. ½ AaBbCcDdEeFf: ½ AaBbCcDdEeff C. 1 AaBbCcDdEeFF: 1 AaBbCcDdEeFf: 1 AaBbCcDdEeff D. 4 AaBbCcDdEeFF: ½ AaBbCcDdEeFf: 4 AaBbCcDdEeff1. Study the given alleles. Write the correct phenotype for each genotype. X – normal Gen otype xC - Color-blind Phenotype XX XY XXC xCY 2. Study the given alleles. Write the correct genotype for each phenotype. xH - Hemophiliac Phenotype X- normal Gen otype Hemophiliac female Hemophiliac male Normal female carrier of the gene Normal male Normal female 28 3. Determine the genotype and phenotype of the offspring. A color-blind mother (XCx) married a normal sighted (XY) father. Genotype: Phenotype: Genotype: Phenotype: Genotype: Genotype: Phenotype: Phenotype: a. There are b. There are c. There are d. There are % normal sons. % normal daughters. % color-blind sons. % color-blind daughters. % normal female, carrier of the disorder. or or or or e. There are or6-8 as they’re all for the same chart Image 1 is phenotypes Image 2 are questions
- 1. Study the given alleles. Write the correct phenotype for each genotype. X– normal Genotype XC – Color-blind Phenotype XX XY XCXC www m XX www w ww w 2. Study the given alleles. Write the correct genotype for each phenotype. X- normal Genotype хн- Hemophiliaс Phenotype Hemophiliac female Hemophiliac male Normal female carrier of the gene Normal male Normal female_30*_SP23 - General Biology I (for maj A 1:1 phenotypic ratio will occur when which of the following crosses is done? us page Select one: F1 O a. Ttx Tt O b. TT x tt O c. TT X TT TTx Tt tt x tt tt x Tt GgTt x GgTt GGTT x ggtt GGtt x ggTT O d. e. O f. O g. Oh. Oi. F2 # 80 F3 LA $ 000 000 F4 % F5 MacBook Air < F6 & F7Trivla Game Show _Make Your Own Tri ngston.schoology.com/common-assessment-delivery/start/4789189591?action=onresume&submissionld=463322566 Dillon WF g Aa v Done In guinea pigs, black hair (B) is dominant to white hair (b) and rough hair (R) is dominant to smooth hair (r). What are all the possible genotypes of a guinea pig that has black, rough hair? (Select all that apply.) O BBRR BBRr BBrr BBRR BbRr O bbRR O bbRr O bbrr O Black O White O Rough OSmooth O Rough O Smooth
- Finally, draw out a Punnett square to help you consider the cross between these possible gametes. Sex-Linked1 := Homework • Unanswered What are the possible genotypes of the offspring shown in your Punnett square? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. XBxb and xbY a b XBXB and xbY Neither of these answers is correct Unanswered • 1 attempt left Submit Sex-Linked2 Homework • Unanswered What are the possible phenotypes of the offspring? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a Females with normal color vision and males who are colorblind Females who are colorblind and males who have normal color visiony 301 Amelogenesis imperfecta is X-linked dominant. Affected XY individuals have extremely thin enamel on the teeth while XX carriers have grooved teeth from uneven deposition of enamel. If an unaffected XY individual were to produce children with a XX carrier partner, a. what would be the expected chance of a XY child being affected with the disease? b. what would be the expected chance of a XY child being affected with the disease?How is this trait inherited? | 1 IV 1 1 2 2 Y-linked O X-linked recessive 2 3 First cousins 3 1 2 3 autosomal dominant autosomal recessive O X-linked dominant 5 4 5 4 3 4