Newton's Second Law says that the acceleration of an object is inversely pro- portional to its mass. However, the acceleration with which all objects fall in the absence of air is the same. How can this be?

Newton's Second Law says that the acceleration of an object is inversely pro- portional to its mass. However, the acceleration with which all objects fall in the absence of air is the same. How can this be?

Name: Newton's Second Law says that the acceleration of an object is invers
Uploaded: 2024-03-20T06:56:46.000Z
Channel: Bartleby
Description: Newton's Second Law says that the acceleration of an object is inversely pro-portional to its mass.However, the acceleration with which all objects fall in the absence of air is thesame. How can this be?

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter5: Newton's Law Of Motion

Section: Chapter Questions

Problem 4CQ: Why can we neglect forces such as those holding a body together when we apply Newton’s second law?

See similar textbooks

Similar questions

A force F-Bi - j – 10k Newton produces an acceleration of 1 ms in a body. The mass of the body is 4. (a) 10 kg (b) 10v2 kg (c) 10/3 kg (d) 200 kg
A crate is acted upon by a net force of 100 N. An accelarationof 5.0 m/s2 results. the weight of the crate is
Albert weights 85kg stands on a scale inside an elevator. Whatis the weight in Newton that the reads when the elevator (a)at rest? (b) moving upward at a constant speed of 3 m/s? (c)moving downward at a constant speed of 5 m/s (d) moving withan upward acceleration of 3 m/s2? (e) moving with an downwardacceleration of 5 m/s2?given:m = 85 kgg = 9.8 m/s2s = 3 m/s (upward)s = 5 m/s (downward)a = 3 m/s2 (upward) a = 5 m/s2 (downward) required: weight @ rest weight upward
Since astronauts in orbit are apparently weightless, a clever method of measuring their masses is needed to monitor their mass gains or losses to adjust diets. One way to do this is to exert a known force on an astronaut and measure the acceleration produced. Suppose a net external force of 57.5 N is exerted and the astronaut's acceleration is measured to be 0.880 m/s². Calculate her mass (in kg). kg By exerting a force on the astronaut, the vehicle in which they orbit experiences an equal and opposite force. Discuss how this would affect the measurement of the astronaut's acceleration. Propose a method in which recoil of the vehicle is avoided.
Holding a long rope by its upper end, youlower it onto a scale. The rope has a mass of 0.13 kg per meterof length, and is lowered onto the scale at the constant rate of1.4 m>s. (a) Calculate the thrust exerted by the rope as it landson the scale. (b) At the instant when the amount of rope at reston the scale has a weight of 2.5 N, does the scale read 2.5 N, morethan 2.5 N, or less than 2.5 N? Explain. (c) Check your answer topart (b) by calculating the reading on the scale at this time.
An igneous rock has a mass of 5 Kg. What is its weight on the moon, where the acceleration due to gravity is one sixth that on Earth? What is ist weight in Jupiter, where the acceleration due to gravity is 2.64 times that on Earth?
The terminal velocity of a human being is 200 km/hr, and it takes about 12 seconds to achieve this. This calculation considers for air friction of course. What would a person’s speed be if they free fell for 12 seconds instead (no air friction present)?
If the rocket sled starts with onlyone rocket burning, what is the magnitude of its acceleration?Assume that the mass of the system is 2100 kg, the thrust Tis 2.4×104 N, and the force of friction opposing the motionis known to be 650 N. (b) Why is the acceleration not onefourth of what it is with all rockets burning?
During a road test, a driver breaks a 1420 kg car moving at 72 km/h [W]. The carslows down and comes to a stop after moving 100 m [W].(a) Calculate the net force acting on the car.(b) What is the force of friction acting on the car while it is slowing down? Explainyour reasoning.
A hockey puck is set in motion across a frozen pond. If ice friction and air resistance are neglected, the force required to keep the puck sliding at constant velocity is (A) Equal to the weight of the puck. (B) The weight of the puck divided by the mass of the puck. (C) The mass of the puck multiplied by 9.8. (D) None of the above. Explain the answer.
A 75.0-kg woman stands on a bathroom scale in an elevator that accelerates from rest to 30.0 m/s in 2.00 s. (a) Calculate the scale reading in newtons and compare it with her weight. (The scale exerts an upward force on her equal to its reading.) (b) What is unreasonable about the result? (c) Which premise is unreasonable, or which premises are inconsistent?
w25 A student weights 700 N is in elevator at rest:(a) How much would a student weight if the elevator accelerates upward at 2m/s2 as in fig(a).(b) How much would a student weight if the elevator accelerates downward at .2m/s2 as in fig(b)