Now assume that the data are from a repeated- measures study using the same sample of n = 6 participants in all three treatment conditions. Use a repeated-measures ANOVA with α = .05 to test the significance of the mean differences. (follow the four-step procedure) B) Compute partial eta square for part A. Report your results of the hypothesis test and effect size in APA format C) Conduct a post hoc analysis for part A using HSD

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
Problem 8CR
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Question

The following data are from an experiment comparing three different treatment conditions

 

 Treatment

 

 

 

 

 I

II

III

P

 

 

6

9

12

27

N = 18

 

8

8

8

24

G = 108

 

5

7

9

21

ΣX2 = 800

 

0

4

8

12

 

 

2

3

4

9

 

 

3

5

7

15

 

 

M = 4

M = 6

M = 8

 

 

 

T = 24

T = 36

T = 48

 

 

 

SS =42

SS = 28

SS = 34

 

 

 

A)

Now assume that the data are from a repeated- measures study using the same sample of n = 6 participants in all three treatment conditions. Use a repeated-measures ANOVA with α = .05 to test the significance of the mean differences. (follow the four-step procedure)

B)

Compute partial eta square for part A. Report your results of the hypothesis test and effect size in APA format

C)

Conduct a post hoc analysis for part A using HSD

Expert Solution
Step 1

(A)

Statistics homework question answer, step 1, image 1

Statistics homework question answer, step 1, image 2

Step 2

 

Result Details
Source

Sum of Squares

SS

Degree of freedom df Mean Square MS F Statistic (The F statistic formula is: F Statistic = variance of the group means / mean of the within group variances)
Between-treatments 48 2 24 F = 3.46154
Within-treatments 104 15 6.9333  
Total 152 17    

The f-ratio value is 3.46154. The p-value is 0.058066

Hypothesis Results : Conclusion

The p-value corresponding to the F-statistic of one-way ANOVA is higher than 0.05, suggesting that the treatments are not significantly different for that level of significance. The Tukey HSD test, as well as other multiple comparison tests like Scheffe or Bonferroni, might not narrow down which of the pairs of treatments are significantly different.

 

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