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- CONVERT THIS INTO C LANGUAGE task 4.s---------password:.byte 0x73,0x65,0x63,0x72,0x65,0x74,0x0.LC0:.byte 0x70,0x6c,0x65,0x61,0x73,0x65,0x20,0x65,0x6e,0x74.byte 0x65,0x72,0x20,0x79,0x6f,0x75,0x72,0x20,0x70,0x61.byte 0x73,0x73,0x77,0x6f,0x72,0x64,0xa,0x0.LC1:.byte 0x25,0x73,0x0main:pushl %ebpmovl %esp,%ebpsubl $12,%esppushl %ebxpushl $.LC0call printfleal -8(%ebp),%eaxpushl %eaxpushl $.LC1call scanfmovl $0,-12(%ebp)leal 12(%esp),%esp.L2:cmpl $7,-12(%ebp)jg .L3movl %ebp,%eaxaddl -12(%ebp),%eaxleal -8(%eax),%eaxcmpb $64,(%eax)jle .L5movl %ebp,%eaxaddl -12(%ebp),%eaxleal -8(%eax),%eaxcmpb $90,(%eax)jg .L5movl %ebp,%eaxaddl -12(%ebp),%eaxleal -8(%eax),%eaxmovl %ebp,%edxaddl -12(%ebp),%edxleal -8(%edx),%edxmovb (%edx),%claddb $32,%clmovb %cl,(%eax).L5:incl -12(%ebp)jmp .L2.L3:pushl $passwordleal -8(%ebp),%eaxpushl %eaxcall strcmpmovl %eax,%ebxleal 8(%esp),%espcmpl $0,%ebxjne .L6xorl %eax,%eaxjmp .L1jmp .L7.L6:movl $-1,%eaxjmp .L1.L7:.L1:leal -16(%ebp),%esppopl %ebxleaveret Sample C program…Translate STUR XO, [X21, #8] to the corresponding LEGV8 machine language:The C programming language supports these bitwise operators: bitwiseAND, bitwise inclusive OR, bitwise exclusive OR, one's complement (unary). & 1. Identify the corresponding instructions in the AVR Instruction Set Manual that the AVR arithmetic and logic unit (ALU) implements.
- What primitive data types can normally be represented and processed by a CPU?C program A decimal number between 0 and 32 exclusive can be expressed in binary system as x4x3x2x1x0, where xi ’s are either zero or one. Write a C program that accepts (from the terminal) a decimal number in the above range and prints out the equivalent binary representation.Convert binary no to decimal in C language.
- Translate LDUR X19, [X21, #40] to the corresponding LEGV8 machine language code:Convert C/C++ code to MIPS CodeWrite programs in MSP430 language for the following questions: a(15 points) Load least significant 6 digits of your student number as ASCII characters (8-bit ASCII) into R4-R5-R6 register set. b(15 points) Add constant 10 to each character of the R4-R5-R6 register set to make a simple encryption and store results into R7-R8-R9. c(15 points) Decrypt R7-R8-R9 by subtracting by 10 and load the results into R10-R11-R12. d-(15 points) Compare the contents of the set of R4-R5-R6 and the set of R10-R11-R12. Load 1 into R13 to show both sets are the same or clear R13. For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac).