• Part A Chemical energy is released or absorbed from reactions in various forms. The most easily measurable form of energy comes in the form of heat, or enthalpy. The enthalpy of a reaction can be calculated from the standard heats of formation of the substances involved in the reaction: Calculate the standard enthalpy change for the reaction Δ.ΗΣn, Δ Η (products)-Σn, Δι Η (reactants) 2A +B= 2C+ 2D where the heats of formation are given in the following table: Here, n, represents the stoichiometric coefficients of the products, n, represents the stoichiometric coeffi cients of the reactants. Substance kJ mol-) The standard entropy change for the reaction, A,S, is a measure of the change in how the energy can be spread out during the course of the reaction. The standard Gibbs energy change for the reaction can be estimated at any temperature using A -243 B -421 A.G = A,H° - TA,S 193 assuming A, H° and A, S° do not change with temperature. D -487 Express your answer in kJ mol A,H° - 319 kJ mol Submit Previous Answers v Correct • Part B For the reaction given in Part A, how much heat is absorbed when 2.50 mol of A reacts? Express your answer numerically in kilojoules. Vo AEO ? kJ • Part C For the reaction in Part A, A S° = 25.0 JK mol. What is the standard Gibbs energy of reaction at 306 K, AG (306K)? Express your answer numerically in kJ mol. να ΑΣφ A,G (306K) = kJ mol Submit Request Answer
• Part A Chemical energy is released or absorbed from reactions in various forms. The most easily measurable form of energy comes in the form of heat, or enthalpy. The enthalpy of a reaction can be calculated from the standard heats of formation of the substances involved in the reaction: Calculate the standard enthalpy change for the reaction Δ.ΗΣn, Δ Η (products)-Σn, Δι Η (reactants) 2A +B= 2C+ 2D where the heats of formation are given in the following table: Here, n, represents the stoichiometric coefficients of the products, n, represents the stoichiometric coeffi cients of the reactants. Substance kJ mol-) The standard entropy change for the reaction, A,S, is a measure of the change in how the energy can be spread out during the course of the reaction. The standard Gibbs energy change for the reaction can be estimated at any temperature using A -243 B -421 A.G = A,H° - TA,S 193 assuming A, H° and A, S° do not change with temperature. D -487 Express your answer in kJ mol A,H° - 319 kJ mol Submit Previous Answers v Correct • Part B For the reaction given in Part A, how much heat is absorbed when 2.50 mol of A reacts? Express your answer numerically in kilojoules. Vo AEO ? kJ • Part C For the reaction in Part A, A S° = 25.0 JK mol. What is the standard Gibbs energy of reaction at 306 K, AG (306K)? Express your answer numerically in kJ mol. να ΑΣφ A,G (306K) = kJ mol Submit Request Answer
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Question
pls. help me with part b and c as they are both calculated together. I really want to make sure i get them right.
![Part A
Chemical energy is released or absorbed from reactions in various forms. The most easily measurable form of
energy comes in the form of heat, or enthalpy. The enthalpy of a reaction can be calculated from the standard
heats of formation of the substances involved in the reaction:
Calculate the standard enthalpy change for the reaction
Δ. ΗΣn, Δι Η' (products) Σ Δ; Η* (reactants)
2A +B= 2C+2D
where the heats of formation are given in the following table:
Here, n, represents the stoichiometric coefficients of the products, n, represents the stoichiometric coeffi cients
Af H°
(kJ mol-1)
of the reactants.
Substance
The standard entropy change for the reaction,A,S°, is a measure of the change in how the energy can be
spread out during the course of the reaction. The standard Gibbs energy change for the reaction can be
estimated at any temperature using
A
-243
B
-421
A;G° = A;H° – TA;S°
C
193
assuming A, H° and A; S° do not change with temperature.
D
-487
Express your answer in kJ mol¬1.
A,H° = 319 kJ mol-1
Submit
Previous Answers
Correct
Part B
For the reaction given in Part A, how much heat is absorbed when 2.50 mol of A reacts?
Express your answer numerically in kilojoules.
ΑΣφ
?
kJ
Part C
For the reaction in Part A, Ar S° = 25.0 J K¯' mol. What is the standard Gibbs energy of reaction at 306 K ,A;G° (306K)?
Express your answer numerically in kJ mol-1.
?
A;G° (306K) =
kJ mo]-1
Submit
Request Answer](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff3336398-7b35-4519-a1b6-0c7e626f349f%2F7056a882-f7ce-4eb7-8135-abfdd3a979b4%2Fc8ur0j_processed.png&w=3840&q=75)
Transcribed Image Text:Part A
Chemical energy is released or absorbed from reactions in various forms. The most easily measurable form of
energy comes in the form of heat, or enthalpy. The enthalpy of a reaction can be calculated from the standard
heats of formation of the substances involved in the reaction:
Calculate the standard enthalpy change for the reaction
Δ. ΗΣn, Δι Η' (products) Σ Δ; Η* (reactants)
2A +B= 2C+2D
where the heats of formation are given in the following table:
Here, n, represents the stoichiometric coefficients of the products, n, represents the stoichiometric coeffi cients
Af H°
(kJ mol-1)
of the reactants.
Substance
The standard entropy change for the reaction,A,S°, is a measure of the change in how the energy can be
spread out during the course of the reaction. The standard Gibbs energy change for the reaction can be
estimated at any temperature using
A
-243
B
-421
A;G° = A;H° – TA;S°
C
193
assuming A, H° and A; S° do not change with temperature.
D
-487
Express your answer in kJ mol¬1.
A,H° = 319 kJ mol-1
Submit
Previous Answers
Correct
Part B
For the reaction given in Part A, how much heat is absorbed when 2.50 mol of A reacts?
Express your answer numerically in kilojoules.
ΑΣφ
?
kJ
Part C
For the reaction in Part A, Ar S° = 25.0 J K¯' mol. What is the standard Gibbs energy of reaction at 306 K ,A;G° (306K)?
Express your answer numerically in kJ mol-1.
?
A;G° (306K) =
kJ mo]-1
Submit
Request Answer
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