Part A The three point charges +4.0 µC, -5.0 µC, and -9.0 µC are placed on the x-axis at the points x = 0 cm, x = 40 cm, and x = 120 cm, respectively. What is the x component of the electrostatic force on the -9.0 µC charge due to the other two charges? (k = 1/4Tte0 = 9.0 × 10º N • m²/c²) O 0.64 N O -0.55 N O -0.41 N O 0.55 N O 0.41 N Submit Request Answer

Principles of Physics: A Calculus-Based Text
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Chapter19: Electric Forces And Electric Fields
Section: Chapter Questions
Problem 1OQ: A point charge of 4.00 nC is located at (0, 1.00) m. What is the x component of the electric field...
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Part A
The three point charges +4.0 µC, -5.0 µC, and -9.0 µC are placed on the x-axis at the points x = 0 cm, x = 40 cm, and x = 120 cm, respectively. What is the x component of the electrostatic force on the -9.0
µC charge due to the other two charges? (k = 1/4TTE0 = 9.0 × 10° N • m2/c2)
0.64 N
-0.55 N
-0.41 N
0.55 N
0.41 N
Submit
Request Answer
Transcribed Image Text:Part A The three point charges +4.0 µC, -5.0 µC, and -9.0 µC are placed on the x-axis at the points x = 0 cm, x = 40 cm, and x = 120 cm, respectively. What is the x component of the electrostatic force on the -9.0 µC charge due to the other two charges? (k = 1/4TTE0 = 9.0 × 10° N • m2/c2) 0.64 N -0.55 N -0.41 N 0.55 N 0.41 N Submit Request Answer
Expert Solution
Step 1

The electrostatic force on a charge q due to another charge Q is given by,

F=14πε0qQr2

where r is the separation between the two charges. The force acts along the line joining the two charges. The force is attractive if the charges are of opposite sign and is repulsive if the charges are of the same sign.

If there are multiple charges, the net force due to all the charges is given by the vector sum of all the forces due to each charge.

In this question, given charges are

q1=+4 μCq2=-5 μCq3=-9 μC

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