Solve it correctly please. Explain in details. I will rate a 5. The value of gravity as an object is thrown upward in FPS.980 cm / s29.8 m / s2- 9.8 m / s232 ft / s2- 32 ft / s2

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Description: Solve it correctly please. Explain in details. I will rate a 5. The value of gravity as an object is thrown upward in FPS.980 cm / s29.8 m / s2- 9.8 m / s232 ft / s2- 32 ft / s2

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5. The value of gravity as an object is thrown upward in FPS. 980 cm / s2 9.8 m / s2 - 9.8 m / s2 32 ft / s2 - 32 ft / s2

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter6: Uniform Circular Motion And Gravitation

Section: Chapter Questions

Problem 33PE: (a) Calculate Earth's mass given the acceleration due to gravity at the North Pole is 9.830 m/s2 and...

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(a) Calculate Earth's mass given the acceleration due to gravity at the North Pole is 9.830 m/s2 and the radius of the Earth is 6371 km from center to pole. (b) Compare this with the accepted value of 5.9791024 kg.
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9. Four identical 2500 kg objects are at the corners of a square with 12 m sides. A. What is the distance between A and B? 12m B. Calculate the force of gravity between A and B. 2.890 x 10 -le C. Calculate the force of gravity between B and D. E. A 25 kg object is then placed at the center of the square (point P). Remembering that force is a vector, calculate the net force on the object at point P. B 12 m 2500 kg -O
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1. At which location is the Earth's gravity the strongest? * a. Inside the Earth b. At the Earth's surface c. At the north pole d. far from the Earth e. None of the above
13. Haleakala, located on the island of Maui has a peak of 3055 m above sea level. Assume that sea level defines the height of Earth's surface. (TE = 6.38 × 106 m, m = 5.98 × 10²4 kg, G = 6.67 × 10-¹¹ Nm²/kg²) a. Calculate the strength of Earth's gravitational field at a point at the peak of Haleakala. b. What is the ratio of the strength of Earth's gravitational field at the top of Haleakala to the strength at a point 64416m below the surface of the Earth? c. A tourist watching the sunrise on top of Haleakala watches a satellite orbiting Earth at an altitude 3580 km above his position. Determine the speed of the satellite.
3. The gravitational acceleration at Earth's surface (ge) is about 10 m/s? and ge = GM/R?. What is gp at the surface of a planet with 2X Earth's mass and 3X Earth's radius?
Using the international system of units (SI system), the unit of the universal gravitational constant (G) is: A. N.m B. N.m/kg C. N/m D. Kg2/N.m E. N.m2/(kg)2
8. A 35 kg object is on the surface of Venus. Venus has a mass of 4.87×1024 kg and a radius of 6.05×106 m. A. What is the weight of the object on the earth (use g = 9.8 m/s²)? 20 487x 10 3kkg B. What is the mass of the object on the earth? C. What is mass of the object on Venus? D. What is weight of the object on Venus?
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12. Escape Velocity To escape Earth's gravitational field, a rocket must be launched with an initial velocity called the escape velocity. A rocket launched from the surface of Earth has velocity v (in miles per second) given by V = 2GM Tº + v² - 2GM R where vo is the initial velocity, r is the distance from the rocket to the center of Earth, G is the gravitational constant, M is the mass of Earth, and R is the radius of Earth (approximately 4000 miles). V= a. Find the value of vo for which you obtain an infinite limit for r as v approaches zero. This value of vo is the escape velocity for Earth. 192,000 T b. A rocket launched from the surface of the moon has velocity v (in miles per second) given by V = 1920 T +v-48 + - 2.17. Find the escape velocity for the moon. c. A rocket launched from the surface of a planet has velocity v (in miles per second) given by 10,600 T + v² - 6.99. Find the escape velocity for this planet. Is the mass of this planet larger or smaller than that of Earth?…