Problem 1: Two 2.0-mm-diameter beads, C and D, are ro = 10 mm apart, measured between their centers (see Fig.1). Bead C has mass mc = 1.0 g and charge qc = 2.0 nC. Bead D has mass mp = 2.0g C and charge qp = -1.0 nC. If the beads are released from rest, what are the speeds uc and up at the instant the beads collide? Partial answer: UD = 4.9 cm/s. a) Write down the energy conservation law for this system. To compute potential energies, use the expression for the potential energy of two point charges (do not plug in the numbers at this step, but work only with symbols). Note that the final potential energy of the system is not zero, and it is determined by the distances between the centers of the beads when they collide. At the end of this step you will have an expression that contains both speeds uc and up, but you will not know yet how to compute them separately. R=1mm 5=10mm O FIG. 1: The scheme for Problem 1 b) In addition to the energy conservation, in this problem you need to use the law of conservation of linear momentum. The linear momentum of this system as a whole is equal to zero. Which relation between the speeds vc and up has to be satisfied to guarantee zero linear momentum (express up in terms of vc, but do not plug in the numerical values yet)? c) Use this expression for up in the energy conservation law from part a) and work out the symbolic formula for vc in terms of mc, mp, qc, qd, ro and R. Only after you have the final formula, plug in the numerical values of the parameters to compute the speed vc. Compute vp from vc.
Problem 1: Two 2.0-mm-diameter beads, C and D, are ro = 10 mm apart, measured between their centers (see Fig.1). Bead C has mass mc = 1.0 g and charge qc = 2.0 nC. Bead D has mass mp = 2.0g C and charge qp = -1.0 nC. If the beads are released from rest, what are the speeds uc and up at the instant the beads collide? Partial answer: UD = 4.9 cm/s. a) Write down the energy conservation law for this system. To compute potential energies, use the expression for the potential energy of two point charges (do not plug in the numbers at this step, but work only with symbols). Note that the final potential energy of the system is not zero, and it is determined by the distances between the centers of the beads when they collide. At the end of this step you will have an expression that contains both speeds uc and up, but you will not know yet how to compute them separately. R=1mm 5=10mm O FIG. 1: The scheme for Problem 1 b) In addition to the energy conservation, in this problem you need to use the law of conservation of linear momentum. The linear momentum of this system as a whole is equal to zero. Which relation between the speeds vc and up has to be satisfied to guarantee zero linear momentum (express up in terms of vc, but do not plug in the numerical values yet)? c) Use this expression for up in the energy conservation law from part a) and work out the symbolic formula for vc in terms of mc, mp, qc, qd, ro and R. Only after you have the final formula, plug in the numerical values of the parameters to compute the speed vc. Compute vp from vc.
Chapter5: Electric Charges And Fields
Section: Chapter Questions
Problem 52P: Suppose Earth and the Moon each carried a net negative charge Q . Approximate both bodies as point...
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Hi, I was wondering if you can help me with PART A,PART B, AND PART C because I am having trouble solving this problem, I was wondering if you can help me and can you also label which part is PART A,PART B AND C. Thank you
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